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andre [41]
3 years ago
12

An ionic bond is made from a ___ and a ___.

Chemistry
1 answer:
Aleksandr [31]3 years ago
8 0
I think the answer is cation, and anion
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If I have ten hydrogen molecules and three oxygen molecules, how many molecules of water can I make and how many leftover?
damaskus [11]

Answer:

3 molecules of water with  4 hydrogen atoms left over

Explanation:

Formula for water is H2O

2 hydrogen per 1 Oxygen

we have 10 H and 3 O

3 0
3 years ago
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What is difference between pie and cake
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Cake is a fluffy tasty dessert with frosting, while pie is a crusty, hardish dessert with fillings such as cherries or apples. Can I plz have brainliest?
5 0
3 years ago
Which is NOT a sign that a double displacement reaction has occurred?
kramer

the coefficients are equal is NOT a sign that a double displacement reaction has occurred

<u>Explanation:</u>

Usually during solutions of two ionic compounds are combined a precipitate (solid) is created. The mix may become cloudy, or may also separate, with the solids falling at the seat of the receptacle. Infrequently, the mix may bubble as a gas or water is produced.

A precipitation reaction is at two aqueous ionic compounds that make a unique ionic compound that is not soluble in water. The insoluble product compound is called the precipitate. The reaction, in this case, is not balanced, which are evaluated  by summing coefficients.

3 0
4 years ago
How many moles are present in
olasank [31]

Answer: (a) There are 0.428 moles present in 12 g of N_{2} molecule.

(b) There are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

Explanation:

(a). The mass of nitrogen molecule is given as 12 g.

As the molar mass of N_{2} is 28 g/mol so its number of moles are calculated as follows.

No. of moles = \frac{mass}{molar mass}\\= \frac{12 g}{28 g/mol}\\= 0.428 mol

So, there are 0.428 moles present in 12 g of N_{2} molecule.

(b). According to the mole concept, 1 mole of every substance contains 6.022 \times 10^{23} atoms.

Therefore, moles present in 12.044 \times 10^{23} particles are calculated as follows.

Moles = \frac{12.044 \times 10^{23}}{6.022 \times 10^{23}}\\= 2 mol

So, there are 2 moles present in 12.044 \times 10^{23} particles of oxygen.

4 0
3 years ago
Please help me pleaseeee
11111nata11111 [884]

Answer:

B.

Explanation:

3 0
3 years ago
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