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MA_775_DIABLO [31]
3 years ago
7

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

?
Chemistry
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln}    *100\%\\\\w/w\%=3.15\%

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

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If there are 94 different kinds of naturally occurring atoms how many different naturally occurring elements are there?
Delicious77 [7]

Answer:

118 elements

Explanation:

Of these 118 elements, 94 occur naturally on Earth.

7 0
3 years ago
As the sun heats the surface of the oceans, two layers of water result. What separates the layers?
Basile [38]

Answer:

Thermocline separate these two layers.

Explanation:

Ocean consist of three major layers on the basis of temperature.

1. Upper layer

2. Deep layer

3. Thermocline

Upper layer:

The first layer is called upper layer which is present on the surface and directly expose to the sun. The sun heat up this upper layer easily and warm it.

Deep layer

The deep layer is present below the thermocline. It is present in deep where sunlight can not approach to it and its temperature remain low.

Thermocline

It is the middle layer, present between the upper and deep layer. It separated the upper layer from deep layer. Its upper portion is warmer while lower is colder.

4 0
3 years ago
Convert the following to Fahrenheit
jeka94

Explanation:

1. 50°F

2. 86°F

3.104°F

4. 98.6°F

5. 32°F

Here is the formula

T(°F) = T(°C) × 9/5 + 32

or

T(°F) = T(°C) × 1.8 + 32

Hope it helps...

4 0
3 years ago
Which statement is true? A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic. A
victus00 [196]

Answer:

A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic.

Explanation:

The spontaneity of a reaction depends on the Gibbs free energy(ΔG).

  • If ΔG < 0, the reaction is spontaneous.
  • If ΔG > 0, the reaction is nonspontaneous.

ΔG is related to the enthalpy (ΔH) and the entropy (ΔS) through the following expression:

ΔG = ΔH - T.ΔS

where,

T is the absolute temperature (always positive)

Regarding the exchange of heat:

  • If ΔH < 0, the reaction is exothermic.
  • If ΔH > 0, the reaction is endothermic.

<em>Which statement is true? </em>

<em>A reaction in which the entropy of the system decreases can be spontaneous only if it is exothermic. </em>TRUE. If ΔS < 0, the term -T.ΔS > 0. ΔG can be negative only if ΔH is negative.

<em>A reaction in which the entropy of the system increases can be spontaneous only if it is endothermic.</em> FALSE. If ΔS > 0, the term -T.ΔS < 0. ΔG can be negative if ΔH is negative.

<em>A reaction in which the entropy of the system decreases can be spontaneous only if it is endothermic.</em> FALSE. If ΔS < 0, the term -T.ΔS > 0. ΔG cannot be negative if ΔH is positive.

<em>A reaction in which the entropy of the system increases can be spontaneous only if it is exothermic.</em> FALSE. If ΔS > 0, the term -T.ΔS < 0. ΔG can be negative even if ΔH is positive, as long as |T.ΔS| > |ΔH|.

6 0
3 years ago
What is the volume of an object with a height of 2.3cm, a width of 2.4cm, a mass of 17.5g, and a length of 20cm?
soldier1979 [14.2K]
Volume is 2.3×2.4×20=110.4 cm^3

there is given an object mass, so maybe you need a density too?

density = mass / volume = 17.5/110.4=0.1581 g/cm^3

5 0
3 years ago
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