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MA_775_DIABLO [31]
3 years ago
7

If you are given the molarity of a solution, what additional information would you need to find the weight/weight percent (w/w%)

?
Chemistry
1 answer:
Ludmilka [50]3 years ago
4 0

Answer:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

Explanation:

Hello,

In this case, since molarity is mathematically defined as the moles of solute divided by the volume of solution and the weight/weight percent as the mass of solute divided by the mass of solution, we need:

- The molar mass of the solute, in order to convert from moles of solute to grams of solute.

- The density of solution, to convert from volume of solution to mass of solution.

For instance, if a 1-M solution of HCl has a density of 1.125 g/mL, we can compute the w/w% as follows:

w/w\%=1\frac{molHCl}{L\ sln}*\frac{36.45gHCl}{1molHCl}*\frac{1L\ sln}{1000mL\ sln}*\frac{1mL\ sln}{1.125g\ sln}    *100\%\\\\w/w\%=3.15\%

Whereas the first factor corresponds to the molar mass of HCl, the second one the conversion from L to mL of solution and the third one the density to express in terms of grams of solution.

Regards.

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How many grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C?
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Answer:

22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C

Explanation:

An ideal gas is characterized by three state variables: absolute pressure (P), volume (V), and absolute temperature (T). The relationship between them constitutes the ideal gas law:

P * V = n * R * T

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In this case you know:

  • P= 7.5 atm
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Replacing:

7.5 atm* 2.3 L=n*0.082 \frac{atm*L}{mol*K} *297K

Solving:

n=\frac{7.5 atm* 2.3 L}{0.082 \frac{atm*L}{mol*K} *297K}

n=0.708 moles

Knowing that oxygen gas is a diatomic gas of molecular form O₂ and its mass is 32 g / mole, you can apply the following rule of three: if 1 mole contains 32 grams, 0.708 moles, how much mass will it have?

mass=\frac{0.708 moles*32 grams}{1mole}

mass= 22.656 grams

<u><em>22.656 grams of oxygen gas are there in a 2.3L tank at 7.5 atm and 24° C</em></u>

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