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PolarNik [594]
3 years ago
5

How many valence electrons are in cbr2cohnh2

Chemistry
1 answer:
marishachu [46]3 years ago
8 0

Answer:

36 valence electrons

Explanation:

Given CBr₂COHNH₂ => Br₂C = C - O - H

                                                    |

                                             H - N - H

#Valence e⁻s  = 2Br + 2C + 3H + 1N + 1O = 2(7) + 2(4) + 3(1) + 1(5) + 1(6)

    = 14 + 8 + 3 + 5 + 6 = 36 valence electrons

Addendum ...

#Bonded e⁻s =  2Br + 2C + 3H + 1N + 1O = 2(8) + 2(8) + 3(2) + 1(8) + 1(8)

   = 16 + 16 + 6 + 8 + 8 = 54 bonded electrons

#Covalent Bonds = #Valence e⁻ - #Bonded e⁻ / 2 = (54 - 36) / 2 = 9 cov. bonds.

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State one advantage of drinking hard water rather than drinking soft water​
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7 0
3 years ago
What material is least likely to be recognized as a mixture by looking under a microscope
I am Lyosha [343]
A homogenous mixture is uniform and thus hard to recognize as a mixture. An example is water.
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4 years ago
The vapour pressure of pure benzene at 20 °C is 75 Torr and that of pure methylbenzene is 25 Torr at the same tempera-ture. In a
ss7ja [257]

Answer:

Benzene: 37.5 Torr

Methylbenzene: 12.5 Torr

Explanation:

By Raoult's Law, each substance in a gas mixture contributes to the total pressure of the mixture proportionally to their respective mole fraction. So,

Ppartial = x*P°

Where x is the mole fraction (0.5 for each one because it's equimolar), and P° is the vapor pressure.

Benzene: Ppartial = 0.5 * 75 = 37.5 Torr

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3 0
3 years ago
Which two substances are among the four major types of organic compounds made by living things?
slega [8]

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C. Proteins

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8 0
3 years ago
Read 2 more answers
For a chemical reaction to be spontaneous at all temperatures, which of the following conditions must be met? a. ΔS° > 0, ΔH°
ladessa [460]

Answer:

b. ΔS° > 0, ΔH° < 0

Explanation:

According the equation of Gibb's free energy -

∆°G = ∆°H -T∆°S

∆°G = is the change in gibb's free energy

∆°H = is the change in enthalpy

T = temperature

∆°S = is the change in entropy .

And , the sign of the  Δ°G , determines whether the reaction is Spontaneous or non - Spontaneous or at equilibrium ,

i.e. ,

if

  • Δ°G < 0 , the reaction is Spontaneous
  • Δ°G > 0 , the reaction is non - Spontaneous
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The reaction has the value for ∆°H < 0 i.e. negative, and ∆°S > 0 i.e. , positive

Now ,

∆°G = ∆°H -T∆°S

= ( - ∆°H ) - T( + ∆°S )

= ( - ∆°H ) - T( ∆°S )  

∆°G = negative

Hence ,

Δ°G < 0 , the reaction is Spontaneous  .

6 0
3 years ago
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