As a result of having increased from a price of $55 to $85, we can say that the stock value increased by<u> 54.55%</u>
The stock was valued at $55 then it increased to $85. First thing to do is to check how much it increased by in dollar terms:
<em>= New price - old price </em>
= 85 - 55
= $30
In percentage terms, this is:
<em>= Increase/ Old price x 100%</em>
= 30 / 55 x 100%
= 54.55%
In conclusion, the stock value increased by 54.55%
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Answer:
C. Personal Reference introduction
Explanation:
This introduction type talks about a subject (State University) by relating the speaker or his experience to the subject.
(A) Quotation is something that is being said by someone. So whether or not this speaker related himself to the university, what he said would still have been taken as a quote or would be put in quotation marks when written down.
(B) A Rhetorical Question is one which is asked without the intent of getting an answer. First of all, there is no question in this speaker's speech.
(D) "Story" would have been the answer if there was no option (C) but the fact that option C exists and more perfectly describes his speech, makes (D) refutable.
Answer:
Mark will have at the end of six years the amount of $25,865.74
Explanation:
According to the given data we have the following:
First investment = 2500
Investment increasing at rate of 10%
Interest rate = 13%
t=6 years
Present value is given by formula = C * [((1+g)^n/(1+i)^n) - 1 ] / (g-i)
C is first value = 2,500
g is increase in investment = 0.10
i is intrest rate = 0.13
n is no of years = 6
Putting values into the equation
P = 2500* [((1+ 0.10)^6/(1+0.13)^6) - 1 ] / (0.10-0.13) 1.771561 2.08195
P = 2500* [((1.10)^6/(1.13)^6) - 1 ] / (-0.03)
P = 2500* [0.8509142870866 - 1 ] / (-0.03)
P = 2500* (-0.14908571)/ (-0.03)
P = 2500* 4.9695236
P=$12,423.809
Future value = P*(1+i)^t
= $12,423.809 *(1+0.13)^6
= $25,865.74
Mark will have at the end of six years the amount of $25,865.74
Answer:
E. 115 boxes.
Explanation:
d: 10 boxes/day
p: 36 boxes/day
n: 365 days
s: $60
H: $24 box/year
D: d*n
D= 10*365= 3650 boxes/year
EPQ = 
EPQ=
EPQ= 158.96 = 159 units
I=Q/P * (p-d)
I=159/36 * (36-10)
I=114.83
115 boxes aproximately
Answer:
Results are below.
Explanation:
Giving the following information:
Purchase price= $80,360
Salvage value= $7,910
Useful life= 7 years
<u>To calculate the annual depreciation, we need to use the following method:</u>
Annual depreciation= (original cost - salvage value)/estimated life (years)
Annual depreciation= (80,360 - 7,910) / 7
Annual depreciation= $10,350
<u>2022:</u>
Annual depreciation= (10,350/12)*2= $1,725
<u>2023:</u>
Annual depreciation= $10,350
