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ryzh [129]
3 years ago
15

A small company employs 3 men and 5 women. If a team of 4 employees is to be randomly selected to organize the company retreat,

what is the probability that the team will have exactly 2 women
Mathematics
1 answer:
Paraphin [41]3 years ago
6 0

Answer:

3/7.

Step-by-step explanation:

The total number of ways to pick 4 out of 8 = 8C4

= 8!/ 4!4!

= 70 ways.

The number of ways when  2 are women =  5C2 * 3

= 10 * 3

= 30.

So the required probability = 30/70

= 3/7.

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PLEASE HELP WILL GIVE BRAINLY POINTS!!!!
Afina-wow [57]

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His percentage is 9/15 = 0.6 x 100 = 60%

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Her percentage is: 12/16 = 0.75 x 100 = 75%

Tony played 20 games and won or tied 14.

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April has the highest percentage so she is the one who should play.

8 0
2 years ago
The combined average weight of an okapi and a llama is 450 kilograms. The average weight of 3 llamas is 190 kilograms more than
Law Incorporation [45]
Let K=average weight of an okapi and L=that of a llama.
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3 0
3 years ago
In how many ways can the letters in the word 'Illinois' be arranged?
xenn [34]

Answer:

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7 0
3 years ago
If LaTeX: m\angle ABF=8s-6m ∠ A B F = 8 s − 6 and LaTeX: m\angle ABE=2\left(s+11\right)m ∠ A B E = 2 ( s + 11 ), find LaTeX: m\a
kolbaska11 [484]

Answer:

<h2><em>2(3s-14)</em></h2>

Step-by-step explanation:

Given the angles ∠ABF=8s-6, ∠ABE = 2(s + 11), we are to find the angle ∠EBF. The following expression is true for the three angles;

∠ABF = ∠ABE + ∠EBF

Substituting the given angles into the equation to get the unknown;

8s-6 = 2(s + 11)+ ∠EBF

open the parenthesis

8s-6 = 2s + 22+ ∠EBF

∠EBF = 8s-6-2s-22

collect the like terms

∠EBF = 8s-2s-22-6

∠EBF = 6s-28

factor out the common multiple

∠EBF = 2(3s-14)

<em></em>

<em>Hence the measure of angle ∠EBF is 2(3s-14)</em>

8 0
3 years ago
Statements apply to the expression 8^3 ?check all that apply
hram777 [196]

Answer: So, 8%3 = 2

Step-by-step explanation:

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2 years ago
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