30(or x)-8=22 I don't know if that is one of the answers or not
let's put value of t in equation.
x = 2√t
x = 2√y
x/2 = √y
(x/2)^2 = y
y = x^2 /4
now let's differentiate it with respect to x.
dy/dx = 2x/4 = x/2
differentiating again wrt to x
d^2y/dx^2 = 1/2
Answer:
25 m by 17.5 m
Step-by-step explanation:
7/2 = 3.5
3.5 * 5 = 15 + 2.5 + 17.5
10/2 = 5
5 * 5 = 25
Area=1/2bh
add them
(1/2)ab+(1/2)c^2+(1/2)ab=
ab+(1/2)c^2
ab+(1/2)(a^2+b^2)
not sure which option to pick there are different preferences on what counts as 'simplified'
4. find area
area=LW
area=105*45=4725
depends on the area of the signs
answer is
4725/(areaof1sign)
anyway, round down your answer because you will have an incomplete sign if you don't
5. area=pir^2
1/2 of it is
area=1/2pir^2
area=(1/4)^2pir^2
area=pi((1/4)r)^2
the radius is now 1/4 of what it was originally, meaning that the diameter is also 1/4 of what it is now
we need to know diamater
answer is 1/4 of current diameter
3. unclear
4. area of 1 sign not given, answer is 4725/(areaof1sign), rounded DOWN to nearest integer
5. (404 error, diameter not found) answer is 1/4 of current diameter
For a polyonomial
P(x)=ax^n+bx^(n-1)...zx^0
when n is odd, the endpoints of the graph point in oposite directions
when n is even, the endpoints of the graph point in same direction
a is the leading term
when a is positive and:
1. n is odd, the graph goes from bottom left to top right
2. n is even, the graph goes from top left to top right
when a is negative and:
1. n is odd, the graph goes from top left to bottom right
2. n is even, the graph goes from bottom left to bottom right
xintercept is where the line crosses the x axis or when y=0
yintercept is where the line crosses the y axis or when x=0
f(x)=1x^3-11x^2+36x-36
leading term is positive and odd degree
graph goes from bottom left to top right, has 1 inflection point
yint, sub 0 for all x's
f(0)=0^3-11(0)^2+36(0)-36
yintercept is y=-36 or (0,-36)
xintercept
set function equal to zero
0=x^3-11x^2+36x-36
factor
0=(x-2)(x-3)(x-6)
x=2,3,6
xintercepts are at x=2,3,6 or (2,0), (3,0) and (6,0)
