Once again the answer is 0. The reason is because the cube is 3 by 3 there is a cube 1 by 1 in the center of the big cube, because it is surrounded by other 1 by 1 cubes that cube doesn't get any sides painted. Therefor there is no possibility for all cubes to have at least one side painted.

3 0

3 years ago

Please let me know if this is correct and if not what is the correct answer. Thanks

vlada-n [284]

There’s nothing on the picture

6 0

2 years ago

Read 2 more answers

can somebody help me simplify this given radical to the lowest form√112a^2 and try to explain it to me in layman's terms

posledela

$\bf \sqrt{112a^2}~~ \begin{cases} 112=2\cdot 2\cdot 2\cdot 2\cdot 7\\ \qquad 2^2\cdot 2^2\cdot 7\\ \qquad (2^2)^2\cdot 7 \end{cases}\sqrt{(2^2)^2\cdot 7\cdot a^2}\implies 2^2a\sqrt{7}\implies 4a\sqrt{7}$

6 0

3 years ago

Y is 5 less than the product of 4 and x

Rudiy27

The answer you are looking for is 4x-5

4 0

3 years ago