1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
wlad13 [49]
3 years ago
14

What are the domain and range of f(x) = |x – 3 | + 6? a. Domain: {x | x is all real numbers} Range: {y | y ≥ 6} b. Domain: {x |

x ≥ 3} Range: {y | y ≥ 6} c. Domain: {x | x is all real numbers} Range: {y | y ≥ – 6} d. Domain: {x | x ≥ 3} Range: {y | y ≥ – 6}

Mathematics
2 answers:
just olya [345]3 years ago
8 0

Answer:

a. Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

This is a modular function. All values inside brackets will result in absolute values. In other words, positive numbers.

And we can solve this problem algebraically and graphically.

f(x) = |x-3|+6

There are no restrictions and this function is continuous since we can proceed and take it out the brackets as we'll proceed.

I) y =|x-3|+6

Assuming the symmetrical values for x and -3, i.e. -x and +3

y=-(x-3)+6

y= -x+3+6

y=-x+9

We have a linear equation with no restriction in the Set of Real Numbers. We can choose any value for x, we'll have another for y.

II) Assuming the same values we did in the brackets.

y= x-3 +6

y=x+3

We have another linear equation with no restriction. We can choose any value for x, we'll have another for y.

Finally, we can affirm that the

Domain is  a number that belongs to this Interval: (-∞,∞) inside the Set of Real Numbers or

D={x∈R} even or just like the way it's been written {x|x is all Real Numbers}

Range

The range of function depends on the value set for x since it's the result of y.

But we can say where it starts. And in case of restrictions where it may not continue.

In this case, the range of the function starts at:

y=|x-3|+6

As the range starts at 6, precisely the point (0,6) no matter which value you pick for x. As the function continues with no restriction and goes on and on we can say the Range belongs to this interval [6, ∞) or {y ∈ R /y≥6}

bearhunter [10]3 years ago
6 0

Answer:

Domain: {x | x is all real numbers} Range: {y | y ≥ 6}

Step-by-step explanation:

Domain is the set of all x values. No operations restrict the domain in this case. The domain is all real numbers.

Range is the set of all y values. Absolute value has a v shape starting at 0. Adding 6 raises this vertex to 6. The range is therefore all numbers greater than or equal to 6.

You might be interested in
Two children own two-way radios that have a maximum range of 3 miles. One leaves a certain point at 1:00 P.M., walking due north
Grace [21]

Answer:

The answer is 21 minutes

Step-by-step explanation:

We use the equation Xf = Xo + vt

1) At 1:00 PM, child one leaves the starting point heading north at a constant velocity of 6 mi/hr or .1 [mi/min] (divide by 60 to convert from [mi/hr] to [mi/min])

2) He walks for 15 minutes before kid 2 starts walking. In 15 minutes he is able to cover 1.5 [mi]

  • x_{1f1} =x_{o} +v_{1} t_{1} \\x_{1f1} =0+.1(15)\\x_{1f1} =1.5 [mi]

3) Now, child 2 starts walking and we know that when the range reaches 3 miles, they won´t be able to communicate. So the sum of the final position of child 1 and child 2 must be 3[mi]

  • Child 1 final position => x_{1f} = x_{1f1} +v_{1} t\\x_{1f} =1.5+v_{1} t
  • Child 2 final position => x_{2f} =0+v_{2} t

4) Sum the equations and equate to 3

  • x_{1f} +x_{2f} =3

5) Substitute the values we already know

  • 1.5+v_{1} t+v_{2}t=3\\ 1.5+.1t+.15t=3\\1.5+.25t=3\\t=\frac{3-1.5}{.25} \\t=6 [min]

6) in 15 + 6 minutes they will be 3miles apart

7) In 21 minutes they will still be able to communicate with one another.

7 0
3 years ago
Zero and negative exponentswrite in simplest for without zero or negative exponents- 17 ⁰
Valentin [98]
-17^0=(-17)^0=1\begin{gathered} (-2)^2\times(-2)^{-5}=(-2)^{2-5} \\ =(-2)^{-3} \\ =\frac{1}{(-2)^3} \\ =\frac{1}{-8} \end{gathered}

Thus, the final answers are 1 and -1/8.

4 0
1 year ago
If p is true and q is false, the pq is Always sometimes never true.
Vinvika [58]
Answer:
pq is never true
8 0
3 years ago
Cell phone companies estimate that the total number of text messages (t) since the beginning of the month can be modeled by t=40
GalinKa [24]

The desired number is the difference between the number of messages sent by the 16th day and the number sent by the 9th day:

... n = t(16) - t(9)

... n = (40×√16) - (40×√9)

... n = 40×(4 - 3) = 40


40 text messages were sent between the ninth and sixteenth day of the month.

4 0
3 years ago
3) Chris wants to order DVD's over the internet. Each DVD costs $15.99 and shipping the entire order
satela [25.4K]

Answer:

He can buy 5 DVD's. (Brainliest please)

4 0
3 years ago
Read 2 more answers
Other questions:
  • Gabriella swims 2 laps per minute. What is the unit rate?
    5·2 answers
  • A reflection and a glide are the same thing. <br> True or false?
    15·1 answer
  • Determine -f(a) for f(x) = 2x, and simplify.<br> X-<br> 1
    8·1 answer
  • Radical function question
    14·1 answer
  • PLEASE HELP ON TIMER!!!!!
    9·1 answer
  • If f(x)=2x-1 and g(x)=x^2-3x-2 find (f+g)(x)
    11·2 answers
  • Solve for d.<br> d<br> -2=d/-1
    15·1 answer
  • On a test, Marcus answered 12 out of the first 15 problems correctly. If this rate continues
    10·1 answer
  • Help for free brainlyest
    15·2 answers
  • I NEED HELP RIGHT AWAY!!!! I'LL GIVE YOU 30 POINTS AND TRY TO MARK YOU AS BRAINLIST.Q: What do you need to do to the equations s
    6·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!