Initially address, Gram-negative in light of the fact that the precious stone violet restrains the development of gram-positive.
Second question, Fermentation: the blend of carb lactose, bile salts, and pH turn it unbiased red since they are enteric and age lactose
Third, we would see the development since it is gram negative microbes.
Fourth
1. coliform microbes (pink settlements in light of the fact that the pH is brought down and they are lactose fermenters)
2. Looseness of the bowels typhoid, and paratyphoid bacilli (tan and straightforward provinces since they are non-fermenters)
Answer:
A fungal cell is an eukaryote with all intracellular, membrane bound organelles. A bacterial cell is basically a prokaryote with a nucleoid. The cell wall composition also varies. It is a lipopolysaccharide layer called peptidoglycan layer in bacteria whereas cell wall of a fungal cell contains complex polysaccharides called chitin and glucans. Bacteria are either autotrophic or heterotrophic whereas fungi are strictly heterotrophic. Bacteria reproduces asexually by binary fission whereas fungi can reproduce either by sexual or by asexual method. Dormant form of fungal cell are called conidiospore or basidiospore or zoospore or ascospore based on their location in hyphae and type of reproduction. In bacteria, dormant forms are called endospores.
Answer:
Uno de los progenitores es heterocigoto para color naranja (Nn) y el otro parental es homocigoto recesivo para gris (nn). Al haber una cruza entre un homocigoto recesivo y un heterocigoto, la 50% de la progenie expresa color naranja (Nn), mientras que el otro 50% expresa color gris (nn).
Explanation:
<u>Datos disponibles:</u>
- Cruce entre peces naranjas y peces grises
- 50% de la F1 son peces grises
- Naranja dominante sobre gris
Podemos nombrar el alelo dominante para color naranja <em>N</em>, y al alelo recesivo para color gris <em>n</em>.
Para que en un cruce entre dos fenotipos distintos, el 50% de la primer camada exprese uno de estos fenotipos, entonces uno de los parentales debe ser heterocigoto, mientras que el otro parental debe ser homocigoto recesivo. De esta forma 50% de la primera generación expresara uno de los fenotipos, mientras que el otro 50% expresará el otro fenotipo.
Supongamos que uno de los parentales lleva el genotipo <em>Nn</em>, y el otro parental es <em>nn</em>.
Cruce:
Parental) Nn x nn
Gametas) N n n n
Fenotipos) Naranja Gris
Cuadro de Punnett) N n
n Nn nn
n Nn nn
F1) 2/4 = 1/2 = 50% de la progenie tendrá genotipo heterocigoto, Nn
2/4 = 1/2 = 50% de la progenie tendrá genotipo homocigota recesivo,
nn
50% de la progenie será color naranja (Nn)
50% de la progenie será color gris (nn)
Explanation:
%DV label= 27%
1 cup of cooked collared greens= aprx 266.60 mg of Calcium
Assuming Clara is...
- a teen, her required adequate intake (RAI)= 1300 mg/ day
- an adult, her RAI= 1000 mg/day
For teenaged Clara
∵27 % DV= 270mg
% daily Calcium= 
= 20.8 ≈ 21%
=0.21
<u>21% of her daily calcium needs is in a cup of cooked collard greens.</u>
Calcium is an essential mineral required by the human body, it is involved in cell signalling, muscular function and homeostasis. Along with fats, fiber, vitamin A and C and iron, calcium makes up part of a recommended daily intake target or DV- these are integral to a balanced diet.
Learn more about energy storage at brainly.com/question/523624
Learn more about homeostasis at brainly.com/question/1601808
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Fermentation occurs in anaerobic respiration, and produces less energy than in aerobic respiration due to the lack of ETC because oxygen is not present.
