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3 years ago

5

Estimate the difference. Use benchmarks with decimal parts of 0, 0.25, 0.50, or 0.75.

1 answer:

S_A_V [24]3 years ago

5 0

Answer:

the estimated answer is B: 2.50.

<em>(</em><em>the</em><em> </em><em>exact</em><em> </em><em>answer</em><em> </em><em>is</em><em> </em><em>2</em><em>.</em><em>4</em><em>8</em><em>,</em><em> </em><em>but</em><em> </em><em>rounding</em><em> </em><em>up</em><em> </em><em>would</em><em> </em><em>make</em><em> </em><em>it</em><em> </em><em>2</em><em>.</em><em>5</em><em>0</em><em>)</em>

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Identify the type of sequence shown in the table below and select the appropriate response. (5 points) n f(n) 1 540 2 500 3 460

Svetradugi [14.3K]

$\bf \begin{array}{ccll}
n&f(n)\\
\text{\textemdash\textemdash\textemdash}&\text{\textemdash\textemdash\textemdash}\\
1&540\\
2&\stackrel{540-40}{500}\\\\
3&\stackrel{500-40}{460}\\\\
4&\stackrel{460-40}{420}\\\\
5&\stackrel{420-40}{380}
\end{array}$

notice, the next term is obtained by subtracting 40 from the "current" one, meaning, is an arithmetic sequence, with a "common difference" of -40.

4 0

3 years ago

Read 2 more answers

A 25 kg rock , is raised to the top of a hill 10 m high. What is the PE of the rock ?

nexus9112 [7]

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$Potential \: \: Energy =(mass) \times (gravity \: acceleration) \times (height) \\$

_________________________________

If gravity acceleration is 10 :

$PE = 25 \times 10 \times 10$

$PE = 2500$

_________________________________

If gravity acceleration is 9.8 :

$PE = 25 \times 9.8 \times 10$

$PE = 25 \times 98$

$PE = 2450$

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3 0

3 years ago

You have a hemisphere with a volume of 6. What is the surface area with a sphere with the same diameter. Round to the nearest th

Vikki [24]

Answer:

(the volume of the hemisphere has no units, so i will suppose that it is 6m^3)

For a sphere of radius R, the volume is:

V = (4/3)*pi*R^3

Where pi = 3.14

And a hemisphere is half of a sphere, then the volume of a hemisphere of radius R is:

V = (1/2)*(4/3)*pi*R^3

We know that the volume of the hemisphere is 6 m^3, then we have the equation:

6 m^3 = (1/2)*(4/3)*3.14*R^3

Now we can solve this for R.

6 m^3 = 2.1*R^3

∛(6 m^3/2.1) = R = 1.41 m

The radius of the hemisphere is 1.41m

Now we want to find the surface of a sphere with this radius (if the radius is the same, then the diameter is the same)

For a sphere of radius R, the surface is:

S = 4*pi*R^2

Then the surface of this sphere is:

S = 4*3.14*(1.41 m)^2 = 24.971 m^2

3 0

3 years ago

First rewrite 10/21 and 4/9 so that they have a common denominator

Tema [17]

Answer:

10/21=30/63

4/9=28/63

Step-by-step explanation:

Find the lcm (least common multiple) of 21 an 9, which is 63. Then divide 21 and 9 separately by 63. The multiply that number by the numerator.

6 0

1 year ago

Domain and range of -3x^2+16x+3

Zarrin [17]

Answer:

＜=16

Step-by-step explanation:

3 0

3 years ago