We are asked to solve for the value of "x" such that when it is added in the original area of the park it will double the area. Let us compute first the area of the original dog park (A1) and the solution is shown below:
Area = Lenght*Width = L*W where L=30 yards and W=20 yards
Area = 30*20
Area = 600 yards squared
Solving for the x, when x is added to both sides which double the area:
A1*2 = (L + 2x)*W
600*2 = (30+2x)*20
1200 / 20 = 30+2x
60 = 30 + 2x
60-30 = 2x
30/2 =x
15 = x
The value of x is 15 yards.
Answer:
What do you need help with
Step-by-step explanation: :)
I don’t know but I’m here for it
A=lw A=370 l=6w-23
370=w(6w-23)
6w^2-23w=370
6w^2-23w-370
Works out to
(W-10) pick this one
+10
W=10
or
(6w+37) is not the answer to choose
-37
6w=-37
/6 /6
W=-6.17
A) 10
B) 10
C) 37
Answer:
y=-6 that would be it. remember slope is rise over run