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balu736 [363]
3 years ago
8

40 to 58 which equation can be used to find t

Mathematics
1 answer:
Montano1993 [528]3 years ago
5 0

Answer:

58-40

Step-by-step explanation:

To find the answer, an easy method to addition is subtraction.

Doing 58 - 40 gives you 18. 40+18 is 58.

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Proper
vlabodo [156]

Answer:

  QR(3), RS(3), PQ(3), ST(11), RP(6), RT(14), SP(9), QT(17)

Step-by-step explanation:

The diagram is not shown, but we assume the points are in the sequence ...

  P, Q, R, S, T

Since QR = RS, R is apparently the midpoint of QS, So ...

23. QR = 6/2 = 3

24. RS = QR = 3

25. PQ = QR = 3

26. ST = PT -PQ -QS = 20 -3 -6 = 11

27. RP = PQ +QR = 3 +3 = 6

28. RT = RS +ST = 3 +11 = 14

29. SP = PQ +QS = 3 +6 = 9

30. QT = QS +ST = 6 +11 = 17

6 0
3 years ago
Calculate 3 over 4 ÷ 5 1 fifth
juin [17]

Answer:3/20

Step-by-step explanation:

3/4/ 5/1

3/4 x 1/5 =3/20

3 0
3 years ago
Read 2 more answers
Divide 12x^4+17^3+8x-40 by x-2
chubhunter [2.5K]

Answer:

12x^3 + 24x^2 + 48x + 104 + (5081/x-2)

Step-by-step explanation:

12x^4 + 17* (17*17) + 8x -40/ x-2

1. remove the parenthesis

12x^4 + !7 * 17 * 17 + 8x -40 / x-2

2. multiply 17 by 17

12x^4 + 289 * 17 + 8x -= 40 /x-2

3. multiply 289 by 17

12x^ = 4913 + 8x - 40 / x-2

4. move 4913

12x^4 + 8x + 4913 - 40 / x-2

5. subtract 40 from 4913

12x^4 + 8x + 4873 / x-2

6. set up polynomials to be divided. if there is not a term for every exponent, insert one with a value of 0

x-2 into 12x^4 + 0x^3 + 0x^2 + 8x + 4873

7. divide the highest order term  in the dividend 12x^4 by the highest order term in divisor x = 12x^3

8. multiply by new quotient term

12x^3 * x-2 = 12x^4 -24x^3

9. the expression needs to be subtracted from the dividend, so change all the signs in 12x^4 - 24x^3

12x^4 + 0x^3 - 12x^4 + 24x^3

10. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+24x^3

11.  pull the next term from the original dividend down into the current dividend

+24x^3 + 0x^2

12.  divide the highest order term in the dividend 24x^3 by the highest order term in divisor x = 24x^2

12x^3 + 24x^2

13. multiply new quotient by the divisor

24x^3 * x-2 = 24x^3 - 48x^2

14. the expression needs to be subtracted from the dividend, so change all the signs in 24x^3 - 48x^2

24x^3 + 0x^2 - 24x^3 + 48x^2

15. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

+48x^2

16. pull the next terms from the original dividend down to the current dividend

+ 48x^2 + 8x

17. divide the highest order term in the dividend 48x^2 by the highest order term in the divisor = 48x

12x^3 + 24x^2 + 48x

18. multiply the new quotient term by the divisor

48x * x - 2 = 48x^2 - 96x

19. the expression needs to be subtracted from the dividend, so change all the signs in 48x^2 - 96x

-48x^2 + 96x

20. after changing the signs, add the last dividend from the multiplied polynomial to find new dividend

48x^2 + 8x - 48x^2 + 96x

= 104x

21. pull the next terms from the original dividend down to the current dividend

+ 104x + 4873

22. divide the highest order term in the dividend 104x by the highest order term in the divisor x = 104

23. divide the new quotient by the divisor

104 * x -2 = 104x - 208

24. the expression needs to be subtracted from the dividend, so change all the signs in 104x - 208

104x + 4873 - 104x + 208 = 5081

25. the final answer is the quotient plus the remainder over the divisor

12x^3 + 24x^2 + 48x + 104 + (5081 / x - 2)

5 0
3 years ago
0.25:1.5 in simplest form
Lelechka [254]
The answer should be   
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3 0
3 years ago
I can’t figure this out
ella [17]

Answer:

See picture

Step-by-step explanation:

3 0
2 years ago
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