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3 years ago

What is your average velocity after going 15 meters east followed by 20 meters

Physics

1 answer:

adelina 88 [10]3 years ago

7 0

Answer:

0.5 m/s

Explanation:

Velocity = displacement/time taken

going 15 meters east and then 20 meters west gives a displacement of 5 meters.

Velocity v = 5/10

= 0.5 m/s

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Explanation:

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4 years ago

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3 years ago

Ezra is pulling a sled, filled with snow, by pulling on a rope attached to the sled. The rope makes an angle θ with respect to t

svetoff [14.1K]

Answer:

Explanation:

Given

rope makes an angle of $\theta$

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applied Force is F

as Force is pulling in nature therefore normal reaction is given by

$F_N=mg-F\sin \theta$

Also $F\cos \theta =f_r$

$f_r=\mu _k\cdot F_N$

$f_r=\mu _k\cdot (mg-F\sin \theta )$

$F\cos \theta =\mu _kF_N$ -------1

$F\sin \theta =mg-F_N$ ---------2

Squaring 1 & 2 and then adding

$F^2=(\mu _kF_N)^2+(mg-F_N)^2$

$F=\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}$

Substitute value of F in 1

$cos\theta =\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}}$

$\theta =cos^{-1}(\frac{\mu _KF_N}{\sqrt{(\mu _kF_N)^2+(mg-F_N)^2}})$

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3 years ago

An object accelerates at 32 m/s² when a force of 71 N is applied to it. What is the object’s mass? show your work

amid [387]

Answer:

Its answer is 2.21 kg.

Explanation:

F =m × a

71 = m × 32

71 ÷ 32 = m

2.21 kg = m

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3 years ago

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4 years ago