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Rashid [163]
3 years ago
12

A disk is free to rotate about an axis perpendicular to the disk through its center. If the disk starts from rest and accelerate

s uniformly at the rate of 2 radians/S2 for 4 s, its angular displacement during this time is
(A) 6 radians
(B) 12 radians
(C) 16 radians
(D) 24 radians
(E) 48 radians
Physics
1 answer:
garri49 [273]3 years ago
3 0

Answer:

(C) 16 radians

Explanation:

The angular displacement is given by the following equation:

\Delta \theta=\omega_i t+\frac{1}{2}\alpha t^2

Here

\Delta \theta Is the angular displacement of the body at the indicated time (t).

\omega_i Is the angular velocity of the body at the initial moment.

\alpha Is the angular acceleration of the body.

The disk starts from rest, so \omega_i=0

Replacing the given values:

\Delta \theta=\frac{1}{2}(2\frac{radians}{s^2})(4s)^2\\\Delta \theta=16 radians

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V125BC [204]

Answer:

A longitudinal wave

Explanation:

6 0
3 years ago
If you could shine a very powerful flashlight beam toward the Moon, estimate the diameter of the beam when it reaches the Moon.
grin007 [14]

To develop this problem it is necessary to apply the Rayleigh Criterion (Angular resolution)criterion. This conceptos describes the ability of any image-forming device such as an optical or radio telescope, a microscope, a camera, or an eye, to distinguish small details of an object, thereby making it a major determinant of image resolution.  By definition is defined as:

\theta = 1.22\frac{\lambda}{d}

Where,

\lambda= Wavelength

d = Width of the slit

\theta= Angular resolution

Through the arc length we can find the radius, which would be given according to the length and angle previously described.

The radius of the beam on the moon is

r = l\theta

Relacing \theta

r = l(\frac{1.22\lambda}{d})

r = 1.22\frac{l\lambda}{d}

Replacing with our values we have that,

r = 1.22*(\frac{(384*10^3km)(\frac{1000m}{1km})(550*10^{-9}m)}{7*10^{{-2}}})

r = 3680.91m

Therefore the diameter of the beam on the moon is

d = 2r

d = 2 * (3690.91)

d = 7361.8285m

Hence, the diameter of the beam when it reaches the moon is 7361.82m

8 0
3 years ago
A baseball player friend of yours wants to determine his pitching speed. you have him stand on a ledge and throw the ball horizo
zhenek [66]

Answer:

The pitching speed of your friend is 33.20 m/s

Explanation:

<em>Lets explain how to solve the problem</em>

Your friend throw the ball horizontally that means the vertical initial

component of velocity is zero (u_{y}=0).

The ball is thrown from a height 4 meters above the ground.

The height h=u_{y}t+\frac{1}{2}gt^{2}

<u><em>Remember:</em></u> the height is negative value because its below the point of

thrown (initial position)

h = -4 m , u_{y}=0 and g = -9.8 m/s²(downward)

<em>Substitute these values in the rule above</em>

⇒ 4=0-\frac{1}{2}(9.8)t^{2}

⇒ -4 = -4.9t² (multiply both sides by -1)

⇒ 4 = 4.9t² (divide both sides by 4.9)

⇒ 0.81633 = t² (take √ for both sides)

⇒ <em>t = 0.9035</em>

Then the time of the ball to land on the ground is 0.9035 seconds

The range of the ball on the ground is 30 m

The range R=u_{x}*t, where u_{x} is the horizontal

component of the initial velocity

R = 30 meters and t = 0.9035

⇒ 30=u_{x}(0.9035) (divide both sides by 0.9035)

⇒ u_{x}=33.20 m/s

<em>The pitching speed of your friend is 33.20 m/s </em>

4 0
3 years ago
15. A body moving with a velocity of 20 m/s begins to accelerate at 3 m/s2. How far does the body move in 5 seconds? A. 137.5 m
Rudik [331]

Answer is B. According to the equation of motion s = vt + 1/2 at2 Where s is distance covered, v is velocity, a is acceleration and t is time taken. So, by putting all the values, we get s = (20)(5) + 1/2 (3)(5)2 s = 100 + 1/2 (3)(25) s = 100 + 1/2 75 s = 100 + 37.5 s = 137.5 meters



7 0
3 years ago
Read 2 more answers
What percent of air by volume is nitrogen​
nlexa [21]

Answer:

78 percent

Explanation:

I guess that's the right answer

5 0
3 years ago
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