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3 years ago

What elements are good conductors of electricity?

1 answer:

kramer3 years ago

6 0

In solids: All metals are good conductors of electricity as they contain free moving electrons. Non-metals doesn't conduct , but we consider Graphite the only non-metal that can conduct electricity for the presence of free moving electrons.

In Liquids ; Ionic compunds contains free moving ions , so they conduct electricity as well .

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What happens to the total mass of a substance undergoing a physical change?

Fudgin [204]

I think that your answer would be A. because matter never just goes away in any situation, even if it gets away from you.

4 0

2 years ago

A wave on a string has a wavelength of 0.90 m at a frequency of 600 Hz. If a new wave at a frequency of 300 Hz is established in

kobusy [5.1K]

Answer:

λ₂ = 1.8 m

Explanation:

given,

wavelength of the string 1 = 0.90 m

frequency of the string 1 = 600 Hz

wavelength of string 2 = ?

frequency of the string 2 = 300 Hz

we now,

$f\ \alpha\ \dfrac{1}{\lambda}$

now,

$\dfrac{f_1}{f_2}=\dfrac{\lambda_2}{\lambda_1}$

$\dfrac{600}{300}=\dfrac{\lambda_2}{0.9}$

λ₂ = 2 x 0.9

λ₂ = 1.8 m

Hence, the wavelength of the second string is equal to λ₂ = 1.8 m

8 0

2 years ago

At what speed (in m/s) will a proton move in a circular path of the same radius as an electron that travels at 8.00 ✕ 106 m/s pe

KonstantinChe [14]

Answer:

4347.8 m/s

Explanation:

It is given that the radius of the circular path traversed by proton and electron is same. Also, we know that magnitude of charge on an electron and proton is same. Magnetic field strength is same for both.

$\frac{m_ev_e^2}{r}=qv_eB\\\frac{m_pv_p^2}{r}=qv_pB\\$

Take the ratio:

$m_ev_e=m_pv_p\\\Rightarrow v_p=\frac{m_e}{m_p}v_e\\\Rightarrow v_p=\frac{1}{1840}\times 8.0\times 10^6 m/s\\\Rightarrow v_p=4347.8m/s$

3 0

2 years ago

an ice cube placed in microwave melts in five minutes and it takes 3.50 kj of energy to melt it. what is the power of the microw

Artist 52 [7]

If the ice absorbed 350,000 joules in 5 minutes, then it absorbed energy
at the rate of

(350,000 joules) / (5 x 60 seconds) =<em> 1,166-2/3 watts</em> .

Surely the ice cube didn't absorb every joule delivered to the cooking chamber,
so the microwave oven's cooking power had to be significantly more than that.

6 0

3 years ago

T/F: Stars die.<br> True<br> False

Yuki888 [10]

Answer:

The answer is true

Explanation:

could you brainliest again they said I plagarized when I didn't

8 0

2 years ago