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luda_lava [24]
3 years ago
6

Juanita is making necklaces to give as presents. She plans to put 15 beads on each necklace. Beadsare sold in packages of 20. Wh

at is the least number of packages she can tp make necklaces and have no beads left over?
Mathematics
2 answers:
PtichkaEL [24]3 years ago
4 0
3 packages because you'll have 15 beads left over. which would complete the use of the packages
Alex Ar [27]3 years ago
3 0
3 packages is the anwer hopefully this helped
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Find the volume of the figure
Nadusha1986 [10]
Just find the base area then multiply it by the height.
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which the total is 38
then multiply 38 by 1, which is the height, so it's 38
8 0
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Altogether, Keisha bought 11/12 of a tank of gas.
6 0
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A farmer keeps a record of the weekly milk yield of his herd of seven cows over a period of six months. He finds that the mean y
zhannawk [14.2K]

Answer:

A farmer keeps a record of the weekly milk yield of his herd of seven cows over a period of six months. He finds that the mean yield is 24 liters. He buys another cow that he is told will produce 28 liters of milk a week. Work out the effect this will have on the mean milk yield of his cows.​

Step-by-step explanation:

Hope it helps<3

8 0
2 years ago
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The lifetime of a certain brand of battery is known to have a standard deviation of 9 hours. Suppose that a random sample of 150
Kobotan [32]

Answer:

The 90% confidence interval for the true mean lifetime of all batteries of this brand is between 39.3 hours and 41.7 hours. The lower limit is 39.3 hours while the upper limit is 41.7 hours.

Step-by-step explanation:

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1 - 0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1 - \alpha.

That is z with a pvalue of 1 - 0.05 = 0.95, so Z = 1.645.

Now, find the margin of error M as such

M = z\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645\frac{9}{\sqrt{150}} = 1.2

The lower end of the interval is the sample mean subtracted by M. So it is 40.5 - 1.2 = 39.3 hours

The upper end of the interval is the sample mean added to M. So it is 40.5 + 1.2 = 41.7 hours

The 90% confidence interval for the true mean lifetime of all batteries of this brand is between 39.3 hours and 41.7 hours. The lower limit is 39.3 hours while the upper limit is 41.7 hours.

7 0
3 years ago
For what value of "a" will the product show below have a purely imaginary value?(with work please)
jeka94
4 + 5 • i Or 1 = 9
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12 is the answer
8 0
3 years ago
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