The correct answer is C !
Answer:
Step-by-step explanation:
An option to buy a stock is priced at $150. If the stock closes above 30 next Thursday, the option will be worth $1000. If it closes below 20, the option will be worth nothing, and if it closes between 20 and 30, the option will be worth $200. A trader thinks there is a 50% chance that the stock will close in the 20-30 range, a 20% chance that it will close above 30, and a 30% chance that it will fall below 20.
a) Let X represent the price of the option
<h3><u> x P(X=x)
</u></h3>
$1000 20/100 = 0.2
$200 50/100 = 0.5
$0 30/100 = 0.3
b) Expected option price

Therefore expected gain = $300 - $150 = $150
c) The trader should buy the stock. Since there is an positive expected gain($150) in trading that stock option.
Answer:
9
Step-by-step explanation:
The table is given below

We can see that the table represents a linear function since by checking its slope.
Using:
- Points (-2,15) and (1,6)
- Points (1,6) and (2,3)

Therefore, the values represent a linear function.
A linear equation is of the form y=mx+b
Therefore:
y=-3x+b
Using the points (7,-12)

Therefore, the y-intercept of the function, represented by the table of values is 9.
Answer:
-3r + 15 ---> answer
Step-by-step explanation:
r < 5
You are going to multiply both sides with 3. The reason being is that 3 is a positive number and the equality sign will not change if you use +3.
3r < 15
Now, subtract 15 from both sides, you will get this:
3r < 15
-15 -15
-------------
3r — 15 < 0
Lastly, using the Modulus function, we are going to add a negative sign to the content of our previous step because it's already negative.
So, -3r + 15 is the final solution if r < 5 in the given equation of l3r-15l
X/3 +4 = 5+x/6
6(x/3 +4 = 5+x/6)
2x+ 24 = 30 +x
x= 6