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IgorC [24]
3 years ago
6

The length of segment qs is units

Mathematics
1 answer:
tigry1 [53]3 years ago
3 0

Answer: QS is 17 Units

Step-by-step explanation:

3x+2=5x-8

X=5

So plug it into 5x-8

5(5)-8=17

You might be interested in
Among 35 students in a class, 20 of them earned A's on the midterm exam, 13 earned A's on the nal exam, and 12 did not earn A's
enyata [817]

Answer:

The correct answer is "\frac{2}{7}".

Step-by-step explanation:

According to the question,

Number of students,

= 35

A ! mid term A,

n(A) = 20

B : final A,

n(B) = 13

Didn't start,

n(A^c \cap B^c) = 12

Now,

⇒ n(A \cup B)=35-12

                   =23

then,

⇒ n(A \cup B)=20+13-23

                   =10

hence,

The probability will be:

⇒ P(A \cap B)=\frac{10}{35}

⇒                 =\frac{2}{7}

7 0
3 years ago
What is Simplify 3^-2 • 3^5
galina1969 [7]

Answer: 3^5 / 3^(-2) = 3^(3)

4 0
3 years ago
Solve equation for X<br> c(x-3)-4=b(x+7)
Alenkasestr [34]
Answer:

c(x-3)-4=b(x+7)
(cx-c•3)-4=b(x+7)
cx-3c-4=b(x+7)
cx-3c-4=bx+b•7
-3c-7b-4=bx-cx
x(b-c)=-3c-7b-4
x(b-c)/b-c = -3c-7b-4/b-c

x=-3c+7b+4/b-c
3 0
3 years ago
The simple interest on a certain sum of money for 2 years at 5% per annum is Rs 320. What will be the compound interest on the s
Brilliant_brown [7]

Answer:

Rs 328

Step-by-step explanation:

Find the <u>principal</u> amount invested.

<u>Simple Interest Formula</u>

I = Prt

where:

  • I = interest earned
  • P = principal
  • r = interest rate (in decimal form)
  • t = time (in years)

Given:

  • I = Rs 320
  • r = 5% = 0.05
  • t = 2 years

Substitute the given values into the formula and solve for P:

⇒ 320 = P(0.05)(2)

⇒ 320 = P(0.1)

⇒ P = 3200

<u>Compound Interest Formula</u>

\large \text{$ \sf I=P\left(1+\frac{r}{n}\right)^{nt} -P$}

where:

  • I = interest earned
  • P = principal amount
  • r = interest rate (in decimal form)
  • n = number of times interest applied per time period
  • t = number of time periods elapsed

Given:

  • P = 3200
  • r = 5% = 0.05
  • n = 1 (annually)
  • t = 2 years

Substitute the given values into the formula and solve for I:

\implies \sf I=3200\left(1+\frac{0.05}{1}\right)^{2} -3200

\implies \sf I=3200\left(1.05\right)^{2} -3200

\implies \sf I=3200\left(1.1025\right) -3200

\implies \sf I=3528-3200

\implies \sf I=328

Therefore, the compound interest on the same sum for the same time at the same rate is Rs 328.

7 0
2 years ago
HELP ASAP plz, 45 pts
torisob [31]

Answer:

She didn't take the LCM, made an error while cross multiplying

x = -6

Step-by-step explanation:

a)she didn't take the LCM before cross multiplying.

Also, didn't cross multiply correctly

b) 1 -2/(x-2) = (x+1)/(x+2)

1 - 2/(x-2) = (x+2-1)/(x+2)

1 - 2/(x-2) = 1 - 1/(x+2)

1 - 2/(x-2) = 1 - 1/(x+2)

-2(x+2) = -1(x-2)

-2x-4 = -x+2

x = -6

8 0
3 years ago
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