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nata0808 [166]
2 years ago
6

on the provided graph, plot the points where the following function crosses the x-axis and the y-axis g(x) = -5^x + 5, what does

the graph look like?
Mathematics
1 answer:
SVEN [57.7K]2 years ago
5 0

Answer:

see image

Step-by-step explanation:

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Answer:

{( \sqrt{ {x}^{ - 3} }) }^{5}  =  ({( {x}^{ - 3}) }^{ \frac{1}{2} } ) ^{5}  \\  \\  =  {x}^{ - 3 \times  \frac{1}{2}  \times 5}   =  {x}^{  -  \frac{15}{2} }  =  \frac{1}{ {x}^{ \frac{15}{2} } }

<em><u>Or ;</u></em>

{( \sqrt{ {x}^{ - 3} } )}^{5}  =  {( \sqrt{ \frac{1}{ {x}^{3} }} })^{5}  = ( { \frac{ \sqrt{1} }{ \sqrt{ {x}^{3} } } })^{5}  \\  \\  =  ( { \frac{1}{ \sqrt{x}  \sqrt{ {x}^{2} } } })^{5}  =  ({ \frac{1}{ x\sqrt{x} }})^{5}   \\  \\  = ( \frac{ {(1)}^{5} }{ {x}^{5} ( \sqrt{x} )^{5} } ) =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{1}{2} \times 5 } }  \\  \\  =  \frac{1}{ {x}^{5}  \times  {x}^{ \frac{5}{2} } }  =  \frac{1}{ {x}^{5}  \sqrt{ {x}^{5} } }  \\  \\  =  \frac{1}{ {x}^{5} \sqrt{ {x}^{4} {x}^{1}  }  }  =  \frac{1}{ {x}^{5}  \sqrt{x}  \sqrt{( { {x}^{2} })^{2} } }  \\  \\  =  \frac{1}{ {x}^{5} {x}^{2}  \sqrt{x}  }  =  \frac{1}{ {x}^{7} \sqrt{x}  }   =  \frac{ \sqrt{x} }{ {x}^{8} }

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1 year ago
What is 2.4(1.8) as w in algebraic form.
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Answer:

2.4*1.8W= 4.32

Step-by-step explanation:


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Step-by-step explanation:

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