What is the range of the following relation: (9,-2) (4, 3) ( 8, 10) (-4, 8)
1 answer:
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Given =
∠lkm = 7x - 5
∠nkm = 3x +9
find = value of∠ lkm.
To proof - let us assume that we takeapoint say n and draw a line nk.
nk is angle bisector it divided angle in two equal parts.
( as shown in the diagram given below)
thus we have
∠lkm = ∠lkn + ∠nkm
7x-5 = 3x+9 +3x +9
x = 23
thus the value of∠ lkm
∠lkm = 7x-5
(put the value of x)
thus
∠lkm = 7×23 - 5
∠lkm = 156°
