Question

How many atoms are in 10.1 g Ne

Answer 1

Answer:

3.01 × 10²³ atoms Ne

General Formulas and Concepts:

Atomic Structure

• Reading a Periodic Tables
• Moles

Stoichiometry

• Using Dimensional Analysis

Explanation:

Step 1: Define

Identify

[Given] 10.1 g Ne

[Solve] atoms Ne

Step 2: Identify Conversions

Avogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.

[PT] Molar Mass of Ne: 20.18 g/mol\

Step 3: Convert

1. [DA] Set up:                                                                                                       $\displaystyle 10.1 \ g \ Ne(\frac{1 \ mol \ Ne}{20.18 \ g \ Ne})(\frac{6.022 \cdot 10^{23} \ atoms \ Ne}{1 \ mol \ Ne})$
2. [DA] Divide/Multiply [Cancel out units]:                                                          $\displaystyle 3.01398 \cdot 10^{23} \ atoms \ Ne$

Step 4: Check

Follow sig fig rules and round. We are given 3 sig figs.

3.01398 × 10²³ atoms Ne ≈ 3.01 × 10²³ atoms Ne