<em>I</em><em> </em><em>do</em><em> </em><em>not</em><em> </em><em>understand</em><em> </em><em>science</em><em> </em><em>but</em><em> </em><em>if</em><em> </em><em>u</em><em> </em><em>ask</em><em> </em><em>me</em><em> </em><em>I</em><em> </em><em>would</em><em> </em><em>have</em><em> </em><em>no</em><em> </em><em>clue</em><em> </em><em>do</em><em> </em><em>u</em><em> </em><em>get</em><em> </em><em>what</em><em> </em><em>I</em><em> </em><em>mean</em>
<span>Option C. It is sodium nitrate because it is a strong electrolyte that comes from a strong acid (HNO3) and a strong base (KOH). It becomes a strong electrolyte when it dissolves in water, its formula is NaNO3, which is a compound that forms nitrate together with potassium nitrate and is obtained by chemical synthesis.</span>
Answer:

Explanation:
Hello!
In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

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