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mote1985 [20]
3 years ago
5

Why is it important to know the major muscle groups in your body? Be specific and detailed as possible with your answer. ​

Chemistry
2 answers:
Rus_ich [418]3 years ago
7 0
Knowing the major muscle groups is important for as stated above and health reasons like knowing whether or not you might have strained a muscle or tore one
MrRissso [65]3 years ago
4 0

Answer:

Knowing the major muscle groups and the weight lifting exercises that work each of these basic muscle groups is very important to improving your body. ... This is a great way to keep your body strong, powerful, mobile, flexible, and healthy.

Explanation:

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How do you find the number of protons for any atom
abruzzese [7]

The number of protons in the nucleus of the atom is equal to the atomic number. So the number of atomic number is equal to the number of protons. hope it helped (:

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3 years ago
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g When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solut
Elden [556K]

Answer:

When copper(II) chloride and sodium carbonate solutions are combined, solid copper(II) carbonate precipitates, leaving a solution of sodium chloride. Write the conventional equation, total ionic equation, and net ionic equation for this reaction.

Explanation:

The word equation for the reaction is:

Copper (II) chloride(aq) + sodium carbonate (aq) ->sodium chloride (aq) +           copper carbonate(s)

The balanced chemical equation of the reaction is:

CuCl_2(aq)+Na_2CO_3(aq)->2NaCl(aq)+CuCO_3(s)

The complete ionic equation is:

Cu^2+(aq)+2Cl^-(aq)+2Na^+(aq)+CO_3^2^-(aq)->2Cl^-(aq)+2Na^+(aq)+CuCO_3(s)\\

The net ionic equation is obtained from the complete ionic equation after removing the spectator ions:

Cu^2^+(aq)+CO_3^2^-(aq)->CuCO_3(s)

5 0
3 years ago
Be sure to answer all parts. Propane (C3H8) is a minor component of natural gas and is used in domestic cooking and heating. (a)
Leokris [45]

<u>Answer:</u>

<u>For a:</u> The balanced chemical equation is given below.

<u>For b:</u> The mass of carbon dioxide produced will be 1.07\times 10^3g

<u>Explanation:</u>

  • <u>For a:</u>

Every balanced chemical equation follows law of conservation of mass.

This law states that mass can neither be created nor can be destroyed but it can only be transformed from one form to another form.

This law also states that the total number of individual atoms on the reactant side must be equal to the total number of individual atoms on the product side.

For the given reaction, the balance chemical equation follows:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(g)

All the substances are present in gaseous state.

  • <u>For b:</u>

By Stoichiometry of the reaction:

1 mole of propane gas produces 3 moles of carbon dioxide gas.

So, 8.11 moles of propane gas will produce = \frac{3}{1}\times 8.11=24.33mol of carbon dioxide gas.

Now, calculating the mass of carbon dioxide using equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}

Molar mass of carbon dioxide = 44 g/mol

Moles of carbon dioxide = 24.33 mol

Putting values in above equation, we get:

24.33mol=\frac{\text{Mass of carbon dioxide}}{44g/mol}\\\\\text{Mass of carbon dioxide}=1070.52g

Hence, the amount of CO_2 produced in the given reaction and expressed in scientific notation is 1.07\times 10^3g

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4 years ago
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