Explanation:
Answer
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The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.
Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O ) = 0
2× ( Oxidation number of Al) +3(−2)=0
2× ( oxidation number of Al) +6
∴ Oxidation number of Al =+3
Answer:
See explanation
Explanation:
In the Rutherford experiment, alpha particles were directed at the same spot on a thin gold foil.
As the alpha particles hit the foil, most of the alpha particles went through the foil. In Rutherford's interpretation, most of the particles went through because the atom consisted largely of empty space.
However, some of the alpha particles were deflected through large angles, in Rutherford's interpretation, the deflected alpha particles had hit the dense positive core of the atom which he called the nucleus.
This accounted for their scattering through large angles throughout the foil in all directions.
Answer:
The answer to your question is the letter C. three times as much
Explanation:
Data
First step = 6 m
Second step = 18 m
Potential energy is the energy stored that depends on its position.
Formula
Pe = mgh
m = mass; g = gravity; h = height
Potential energy of the first step
Pe1 = 6mg
Potential energy of the second step
Pe2 = 18mg
-Divide the Pe2 by the Pe1
Pe2/Pe1 = 18mg/6mg
= 3
B
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