The formula for density is:

We know the density for mercury is 13.6 g/mL, and we know the mass of the sample is 53.8 g. Thus, we can plug these numbers into our equation and solve for volume.
The volume is unknown, so we can simply denote it as "x"

multiply both sides by x

The x's cancel out on the right side and you are left with

From here, simply divide both sides of the equation by 13.6 g/mL and solve for x.


Round to 3 significant figures, and your final answer is:

The volume of the sample of mercury was 3.96 mL.
C) is correct, because there are 2 carbons and 4 oxygens on both sides, making the equation balanced.
Answer:The molar mass of a compound cab be find by adding up all the molar mass of the element present in the compound... Check the image for more clarification
Explanation:
To solve this, we should follow order of operations. To start, we should multiply the values inside of the parentheses.
(34.6785*5.39)+435.12
186.917115+435.12
Now, we should add the 2 values we are left with together.
186.917115
<span><u>+435.120000</u>
</span> 622.037115
Using the math above, we can see that this expression is equal to 622.037115.
The correct answer is B. Low chemical reactivity