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Tatiana [17]
3 years ago
5

The value of y is directly proportional to the value of x. If y=24 when x=3, which is the value of x when y=36?

Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0
The correct and good and best and right and ok answers is going to be 12
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Find the quotient. Write the answer in simplest form.
mariarad [96]

Answer:

A) 28/39

Step-by-step explanation:

\frac{4}{13} divided by \frac{3}{7}=\frac{4}{13}*\frac{7}{3}\\=\frac{28}{39}\\Keep the first number. Flip the second number. Change the operation- division into multiplication.

8 0
3 years ago
The formula for potential energy is P = mgh. Solve the equation for h.
Liono4ka [1.6K]

Answer:

P = mgh

P/mg = h

We can divide both sides by mg, since both mass and gravity are being multiplied and not added.

Hope this helps!! :)

Step-by-step explanation:

7 0
2 years ago
What is the monthly payment on a 15-year loan of $72,700 if the annual interest rate is 12%?
Trava [24]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
A simple die is thrown 100 times and the number five appears 14 times. Find the experimental probability of throwing a five, giv
mario62 [17]

Answer:

The experimental probability of throwing a five is 0.087.

Step-by-step explanation:

Given:

Number of trials (n) = 100

Number of times 5 appears (x) = 14

Let the event of occurrence of 5 be success and the probability represented by 'p'. So, all the other numbers occurrence is failure and its probability is represented as 'q'.

Probability of success is given as:

p=\frac{Number\ of\ favorable\ events}{Total\ number\ of\ outcomes}

Favorable event is occurrence of 5. So, its number is 1 as there is only one 5 in the die. Total outcomes are 6 as there are six numbers. So,

p=\frac{1}{6}

Now, probability of failure is given by the formula:

q=1-p=1-\frac{1}{6}=\frac{5}{6}

Now in order to find the experimental probability of 14 successes out of 100 trials, we apply Bernoulli's theorem which is given as:

P(x) = ^nC_xp^xq^{n-x}

Plug in all the given values and find the probability of 14 successes. This gives,

P(x=14)=^{100}C_{14}(\frac{1}{6})^{14}(\frac{5}{6})^{100-14}\\\\P(x=14)=0.087

Therefore, the experimental probability of throwing a five is 0.087.

8 0
3 years ago
Please help, I'm really confused with these two questions ):
erik [133]

Step-by-step explanation:

The die is rigged, so "not 3" is not a possibility.  Ruling out those branches of the tree, there are 4 possible outcomes, one of which is the desired outcome.  So the probability is 1/4.

A fair die has six sides that are equally likely, so the probability of rolling more than 2 is always 4/6.  The outcome of the first roll does not effect the outcome of the second roll.

7 0
3 years ago
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