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Charra [1.4K]
3 years ago
13

Pls slove this question

Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Answer:

The factor is 4xz exponent is 2 (8y with the exponent of 2. x with the exponet of of 5 - 7z

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A rectangular prism. The rectangular base has a length of 5 centimeters and width of 4 centimeters. What are the dimensions of t
AVprozaik [17]

Answer:

dimension is 5cm * 4 cm

Step-by-step explanation:

As the plane is parallel to the base, the ratio between plane's length and width is equal to the ratio of that of the base. -> similar shape.

Moreover, it also divided the rectangular prism into 2 smaller rectangular prism. hence the plane is identical to the base. Hence, same dimension.

see photo

3 0
3 years ago
What is 89/100 as a percent?
masya89 [10]
89/100 as a precent is is 89% because if you change 89/100 to a decimal you get .89 and then you multiply that by 100 (or just move the decimal over 2 places to the right) and you will get 89% make since? and its the same way if your going from % to decimal except you divide by 100( or move the decimal over 2 places to the left) so to a percent is right and to a decimal is left. easy right?
4 0
3 years ago
Read 2 more answers
Initially 100 milligrams of a radioactive substance was present. After 6 hours the mass had decreased by 3%. If the rate of deca
Hitman42 [59]

Answer:

The half-life of the radioactive substance is 135.9 hours.

Step-by-step explanation:

The rate of decay is proportional to the amount of the substance present at time t

This means that the amount of the substance can be modeled by the following differential equation:

\frac{dQ}{dt} = -rt

Which has the following solution:

Q(t) = Q(0)e^{-rt}

In which Q(t) is the amount after t hours, Q(0) is the initial amount and r is the decay rate.

After 6 hours the mass had decreased by 3%.

This means that Q(6) = (1-0.03)Q(0) = 0.97Q(0). We use this to find r.

Q(t) = Q(0)e^{-rt}

0.97Q(0) = Q(0)e^{-6r}

e^{-6r} = 0.97

\ln{e^{-6r}} = \ln{0.97}

-6r = \ln{0.97}

r = -\frac{\ln{0.97}}{6}

r = 0.0051

So

Q(t) = Q(0)e^{-0.0051t}

Determine the half-life of the radioactive substance.

This is t for which Q(t) = 0.5Q(0). So

Q(t) = Q(0)e^{-0.0051t}

0.5Q(0) = Q(0)e^{-0.0051t}

e^{-0.0051t} = 0.5

\ln{e^{-0.0051t}} = \ln{0.5}

-0.0051t = \ln{0.5}

t = -\frac{\ln{0.5}}{0.0051}

t = 135.9

The half-life of the radioactive substance is 135.9 hours.

6 0
2 years ago
A hot air balloon hovers 75 feet above the ground. The balloon is tethered to the ground
DIA [1.3K]

Angle of elevation is 37°

<u>Step-by-step explanation:</u>

As we have the opposite side 75 ft to the angle and the hypotenuse 125 ft, we can find the sine value as,

sin θ = opp/ hyp

       = 75/125

     = 0.6

θ = sin⁻¹ (0.6) = 36.9°≈ 37°

So angle of elevation is 37°.

3 0
3 years ago
My teacher says theres 3 correct answers
Anettt [7]
All of them except the second one .
3 0
3 years ago
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