Answer:
-7(5-u)
Step-by-step explanation:
-7(5-u)
-7x5 -7x-u
-35+7u
Answer:
The right answer is:
a.H0: μd = 0; H1: μd > 0
Step-by-step explanation:
The claim that want to be tested is that the sales were significantly increased after the commercial, indicanting that the advertisement campaign was effective.
This claim is usually expressed in the alternative hypothesis as it has to have enough evidence to prove that it is true.
Then, the alternative hypothesis H1 should state that the difference (sales after - sales before) is higher than 0.
The null hypothesis would state that the difference is not significantly different from 0, or, in other words, that the sales are the same before and after and that the variation is due to pure chance.
Then, the null hypothesis H0 would state that the difference is equal to 0.
The right answer is:
a.H0: μd = 0; H1: μd > 0
<span>15<span>(<span>6−g</span>)</span></span><span>=<span><span>(15)</span><span>(<span>6+<span>−g</span></span>)</span></span></span><span>=<span><span><span>(15)</span><span>(6)</span></span>+<span><span>(15)</span><span>(<span>−g</span>)</span></span></span></span><span>=<span>90−<span>15g</span></span></span><span>=<span><span>−<span>15g</span></span>+<span>90</span></span></span>
P(-2.57 ≤ Z ≤ 1.27) = P(Z ≤ 1.27) - P(Z ≤ -2.57)
P(Z ≤ 1.27) = 0.8980
P(Z ≤ -2.57) = 1 - P(Z ≤ 2.57) = 1 - 0.99488 = 0.00512
P(-2.57 ≤ Z ≤ 1.27) = 0.8980 - 0.00512 = 0.89288
0.8929 (4 d.p.)
The scale for the model length of the fuselage obtained by taking the ratio of the model length and the actual length is 0.125
Actual Length of fuselage = 170 feets
Length of fuselage on model = 21.25
<u>To obtain the scale of the model, we take the ratio of the model length and the actual length</u> :
- Model length / Actual length
- 21.25 feets / 170 feets = 0.125
Therefore, the scale for the model length of the fuselage is 0.125
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