Find the 27th term of a sequence where the first term is – 7 and the common difference is 7.

1 answer:

8 0

Answer:

175

Explanation:

1. an (any term) = 27
2. a1 (first term) = -7
3. d (common difference) = 7

• Use the explicit formula:

an = d(n - 1) + a1

a27 = 7(27 - 1) - 7

- Subtract inside the parenthesis ():

a27 = 7(26) - 7

- Distribute:

a27 = 182 - 7

- Subtract:

a27 = 175

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Which of the following best describes the solution to the equation below?

kozerog [31]

D)One solution. b=5
Distribute 2 times b plus 2 times 3
2b+6
2b+6+2b=26
Combine like terms 4b+6=26
Subtract 6 from both sides
4b=20
Divide both sides by 4
b=5

Check by substituting 5 for b
2 (5+3)+2(5)=26
2(8) + 2(5)=26
16+10=26
26=26

4 0

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Which function is undefined for x = 0? y=3√x-2 y=√x-2 y=3√x+2 y=√x=2

Mkey [24]

For this case, we have to:

By definition, we know:

The domain of $f (x) = \sqrt [3] {x}$ is given by all real numbers.

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So, we have:

$y = \sqrt [3] {x-2}$ with $x = 0$ : $y = \sqrt [3] {- 2}$ is defined.

$y = \sqrt [3] {x+2}$ with $x = 0:\ y = \sqrt [3] {2}$ is also defined.

$f (x) = \sqrt {x}$ has a domain from 0 to ∞.

Adding or removing numbers to the variable within the root implies a translation of the function vertically or horizontally. For it to be defined, the term within the root must be positive.

Thus, we observe that:

$y = \sqrt {x-2}$ is not defined, the term inside the root is negative when $x = 0$ .