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2 years ago

Binomial theorem to expand (x+4)^4

Mathematics

1 answer:

Lilit [14]2 years ago

6 0

Answer:

Step-by-step explanation:

(x+4)^2.(x+4)^2

= x^4 +16x^3+96x^2+256x+256

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Find the 8th term of the geometric sequence 7,28,112,...

oksian1 [2.3K]

Answer:

114,688

Step-by-step explanation:

the previous term is multiplied by 4 to get the next term.if you continue with this sequence you would eventually get 114 688

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2 years ago

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Give the domain of f(x) = 9^(x-4) +7

Lena [83]

D) All Real Numbers.

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2 years ago

Jennifer began a savings account. She initially put $100 in the account and then

vitfil [10]

Jennifer would have $580 in her account after 24 months

a(x) = 20x + 100

the above function is a linear function

A linear function is a function that has a single variable raised to the power of 1.

100 is the constant

20 increases by m

a(x) is the dependent variable. Its value depends on the amount deposited per month and the number of months

The amount she would have after 24 months =

20(24) + 100 = $580

To learn more about linear functions, please check : brainly.com/question/20286983?referrer=searchResults

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2 years ago

Evaluate the following integral using trigonometric substitution.

wariber [46]

Answer:

Step-by-step explanation:

1. Given the integral function $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ , using trigonometric substitution, the substitution that will be most helpful in this case is substituting x as $asin \theta$ i.e $x = a sin\theta$ .

All integrals in the form $\int\limits {\sqrt{a^{2} -x^{2} } } \, dx$ are always evaluated using the substitute given where 'a' is any constant.

From the given integral, $\int\limits {7\sqrt{49-x^{2} } } \, dx = \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx$ where a = 7 in this case.

The substitute will therefore be $x = 7 sin\theta$

2.) Given $x = 7 sin\theta$

$\frac{dx}{d \theta} = 7cos \theta$

cross multiplying

$dx = 7cos\theta d\theta$

3.) Rewriting the given integral using the substiution will result into;

$\int\limits {7\sqrt{49-x^{2} } } \, dx \\= \int\limits {7\sqrt{7^{2} -x^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -(7sin\theta)^{2} } } \, dx\\= \int\limits {7\sqrt{7^{2} -49sin^{2}\theta } } \, dx\\= \int\limits {7\sqrt{49(1-sin^{2}\theta)} } } \, dx\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, dx\\since\ dx = 7cos\theta d\theta\\= \int\limits {7\sqrt{49(cos^{2}\theta)} } } \, 7cos\theta d\theta\\= \int\limits {7\{7(cos\theta)} }}} \, 7cos\theta d\theta\\$

$= \int\limits343 cos^{2} \theta \, d\theta$

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3 years ago

Write863.141 In expanded form

skad [1K]

Answer:

800+60+3+0.1+0.04+0.001

6 0

3 years ago