Answer:
m<T = , m<M = and m<Z =
Step-by-step explanation:
From the given ∆TMZ, let the measure angle T be represented by T.
So that,
m<M = 2T + 6°
m<Z = 5T - 50°
Sum of angles in a triangle =
T + (2T + 6°) + (5T - 50°) =
8T - =
8T = +
=
T =
=
Therefore,
i. m<T =
ii. m<M = 2T + 6°
= 2 x + 6°
=
m<M =
iii. m<Z = 5T - 50°
= 5 x - 50°
= - 50°
=
m<Z =
This is a geometric sequence because each term is twice the value of the previous term. So this is what would be called the common ratio, which in this case is 2. Any geometric sequence can be expressed as:
a(n)=ar^(n-1), a(n)=nth value, a=initial value, r=common ratio, n=term number
In this case we have r=2 and a=1 so
a(n)=2^(n-1) so on the sixth week he will run:
a(6)=2^5=32
He will run 32 blocks by the end of the sixth week.
Now if you wanted to know the total amount he runs in the six weeks, you need the sum of the terms and the sum of a geometric sequence is:
s(n)=a(1-r^n)/(1-r) where the variables have the same values so
s(n)=(1-2^n)/(1-2)
s(n)=2^n-1 so
s(6)=2^6-1
s(6)=64-1
s(6)=63 blocks
So he would run a total of 63 blocks in the six weeks.
Which equation is not equvilant It is c
To find the total length of the two copper pipes, we need to add them together.
2 5/12 + 3 7/12 = 5 12/12
Since 12/12 = 1 or a whole, we can simplify this further.
5 12/12 = 6
Hope this helps!
The second attachment I solved in your another question.You may refer to that.
#1
Apply Pythagorean theorem
x²=10²-6²
