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slavikrds [6]
3 years ago
14

Please show me how to put 0.64 into a fraction

Mathematics
1 answer:
BigorU [14]3 years ago
8 0

Answer:

64/100 is 0.64 into a fraction

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Sovle for X. Please.
Sati [7]
Answer:
RP: x equals 0
JH: x equals -11
EG: x equals 9
5 0
3 years ago
4cos(10x)+2=2<br><br> What would this equal in Degrees??
Ipatiy [6.2K]

Answer:

Simplifying

4cos(10x) + 2 = 2

Remove parenthesis around (10x)

4cos * 10x + 2 = 2

Reorder the terms for easier multiplication:

4 * 10cos * x + 2 = 2

Multiply 4 * 10

40cos * x + 2 = 2

Multiply cos * x

40cosx + 2 = 2

Reorder the terms:

2 + 40cosx = 2

Add '-2' to each side of the equation.

2 + -2 + 40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

0 + 40cosx = 2 + -2

40cosx = 2 + -2

Combine like terms: 2 + -2 = 0

40cosx = 0

Solving

40cosx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Divide each side by '40'.

cosx = 0.0

Simplifying

cosx = 0.0

The solution to this equation could not be determined.

Step-by-step explanation:

7 0
3 years ago
PLEASE HELP!!<br> Write Y=x^2+4x+3 in standard form
DanielleElmas [232]

Answer:

already in standard form

Step-by-step explanation:

the equation of a quadratic in standard form is

y = ax² + bx + c ( a ≠ 0 )

y = x² + 4x + 3 ← is in standard form

with a = 1 , b = 4 , c = 3

6 0
2 years ago
Equation practice with angle addition
Triss [41]

Answer:

36 degrees

Step-by-step explanation:

since, m<AOB is a right angle, we shall just create an equation:

M<AOB+M<BOC=90 degrees

Substitute: 6z-12+3z+30=90

Solve: 6z+3x=9z

-12+30=18

so, 9z+18=90 degrees

           -18  -18

9z=72

z=8

So if z=8, then we should fit it so that it matches measure of AOB.

6z-12

6 times 8=48

48-12= 36

6 0
2 years ago
Difference of Squares gives which complex factors for the expression x2 +3?
Andreas93 [3]

Step-by-step explanation:

Shortest way to solve this question is to find the factors of the given expression.

The given expression is (x² + 13).

Now we have to factorize it.

(x² + 13) = x² + (√13)²

            = x² + [-(i)²√(13)²]  [Since i = √(-1)]

            = x² - (i√13)²

            = (x - i√3)(x + i√3) [Since (a² - b²) = (a + b)(a - b)]-by-

5 0
2 years ago
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