M∠LON=77 ∘ m, angle, L, O, N, equals, 77, degrees \qquad m \angle LOM = 9x + 44^\circm∠LOM=9x+44 ∘ m, angle, L, O, M, equals, 9,
timama [110]
Answer:
Step-by-step explanation:
Given
<LON = 77°
<LOM = (9x+44)°
<MON = (6x+3)°
The addition postulate is true for the given angles since tey have a common point O:
<LON = <LOM+<MON
Since we are not told what to find we can as well look for the value of x, <LOM and <MON
Substitute the given parameters and get x
77 = 9x+44+6x+3
77 = 15x+47
77-47 = 15x
30 = 15x
x = 30/15
x = 2
Get <LOM:
<LOM = 9x+44
<LOM = 9(2)+44
<LOM = 18+44
<LOM = 62°
Get <MON:
<MON = 6x+3
<MON = 6(2)+3
<MON = 12+3
<MON = 15°
(2x-15) + 11x = 180
Combine your like terms in get
13x - 15 = 180
Add 15 on both sides
13x - 15 = 180
+15 + 15
13x = 195
Divide each side by 13 and get
x = 15
To find the area of a regular polygon, all you have to do is follow this simple formula: area = 1/2 x perimeter x apothegm. Here is what it means: Perimeter = the sum of the lengths of all the sides. Apothegm = a segment that joins the polygon's center to the midpoint of any side that is perpendicular to that side.
Answer:
ln(2) +3ln(a) -4ln(b)
Step-by-step explanation:
__
The applicable rules of logarithms are ...
log(ab) = log(a)+log(b)
log(a^b) = b·log(a)
