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Harman [31]
3 years ago
11

S = 40, u 12, mZS = 37

Mathematics
1 answer:
Leni [432]3 years ago
3 0
What do you need help with?
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You burn 5 calories each minute you bike. What integer represents the change in your calories
PtichkaEL [24]

Answer:

150

Step-by-step explanation:

7 0
3 years ago
I just need #1 plzzzz if you can do #2 and #3 as well I also need the work!! 20 points
Agata [3.3K]
#1 would be 12 cm as the actual length of the thermos! This is because the scale given is 1:3 right? if you find what number 1 is multiplied by to get 3, you will obviously have 3. then, the given length of the thermos would be multiplied by 3, so it would be 3 x 4, which would be 12!

-8th grader
3 0
3 years ago
At the beginning of 2009 Marilyn invested $5000 in a savings account account pays 4% interest per year at the end of the year at
solong [7]

Answer:

$5200

Step-by-step explanation:

Given :

Amount invested, Principal, P = $5000

Interest rate, r = 4% = 4/100 = 0.04

Amount in account at the end of the year, A

period, t = 1 year

Using the relation :

A = P(1 + rt)

A = $5000(1 + 0.04*1)

A = $5000(1 + 0.04)

A = $5000 * 1.04

Amount in account at year end = $5200

8 0
3 years ago
Wat digits can be in the ones place of a number that has 5 as a factor?
Ilya [14]
Maybe 50 from 5•10 so 0 can be in the ones place
3 0
3 years ago
Y'all I am struggling Use the following functions to find each value below. f(x)=5x; g(x)=−2x+1; h(x)=x2+6x+8
Anni [7]

Answer:

see below the first three problems

Step-by-step explanation:

f(g(-2))

First, find g(-2) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(-2) = -2(-2) + 1

g(-2) = 5

f(x) = 5x

f(5) = 5(5)

f(5) = 25

f(g(-2)) = 25

g(h(3))

First, find h(3) using function h(x). Then use that value as input for function g(x).

h(x) = x^2 + 6x + 8

h(3) = 3^2 + 6(3) + 8 = 9 + 18 + 8

h(3) = 35

g(x) = -2x + 1

g(35) = -2(35) + 1 = -70 + 1

g(35) = -69

g(h(3)) = -69

f(g(3a))

First, find g(3a) using function g(x). Then use that value as input for function f(x).

g(x) = -2x + 1

g(3a) = -2(3a) + 1

g(3a) = -6a + 1

f(x) = 5x

f(-6a + 1) = 5(-6a + 1)

f(-6a + 1) = -30a + 5

f(g(3a)) = -30a + 5

5 0
3 years ago
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