What Group is this element in? (Urgent plz help)

The temperature in a town started out at 55 degrees. By the end of the day the temperature dropped to -6 degrees.

garik1379 [7]

Answer:

The choice of the answer is fourth option that is -61 degrees.

Therefore the temperature drop is -61°Centigrade.

Explanation:

Given:

The temperature in a town started out at 55 degrees

Start temperature = 55°Centigrade. (Initial temperature)

End of the Day = -6°Centigrade. (Final temperature)

To Find:

How far did the temperature drop?

Solution:

We will have,

$\textrm{Temperature drop}=\textrm{Final temperature}-\textrm{Initial temperature}$

Substituting the above values in it we get

$\textrm{Temperature drop}=-6-55\\\\\therefore \textrm{Temperature drop}=-61\° centigrade$

Therefore the temperature drop is -61°Centigrade.

4 0

3 years ago

Which is a fossil fuel? A.nuclear B.Biomass C.geothermal D.coal

Nat2105 [25]

Answer:

Coal

Explanation:

Coal is composed of the remains of dead animals and plants, being pressed down over the course of thousands of years.

(Also can I please have Brainliest? I need it to level up)

8 0

3 years ago

Read 2 more answers

which nonmetals could form an ionic compound with the formula MgX^2 ( where X represents the nonmetal)? (possible, not possible)

djverab [1.8K]

Answer:

The answer to your question is:

Explanation:

Ionic compound is formed when a metal and a nonmetal are attached.

If we have MgX₂, that means that the nonmetal must have a valence of -1.

From the list the nonmetals with a valence of -1 are:

Bromine(Br) and fluorine(F).

7 0

3 years ago

In the molecules below, areas that have a partial negative charge are pink and areas that have a partial positive charge are blu

Kaylis [27]

Answer:

Dipole-dipole interactions

Step-by-step explanation:

Each molecule consists of two different elements.

Thus, each molecule has permanent bond dipoles.

The dipoles do not cancel, so the attractive forces are dipole-dipole attractions.

"Covalent bonds" is wrong, because there are no bonds between the two molecules.

There are dipole-induced dipole and London dispersion forces, but they are much weaker than the dipole-dipole attractions.

4 0

3 years ago

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

Answer: The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

Explanation:

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

2 years ago