Answer:
[CH₃COOH] = 1.70 M
Explanation:
When we talk about concentration we can determine Molarity
Molarity determines the moles of solute that are contained in 1L of solution.
In this case our solute is the acetic acid.
M = mol/L
M = 0.99 mol /0.58L → 1.70 M
We can also make a rule of three
In 0.58 L of solution we have 0.99 moles of solute
In 1 L of solution we may have (1 . 0.99) / 0.58 = 1.70 moles
Acetic acid is a weak acid, partially dissociated in water.
CH₃COOH + H₂O ⇄ CH₃COO⁻ + H₃O⁺ Ka
Answer:
a. The resonance effect of the hydroxyl group stabilizes the anionic intermediate
Explanation:
The resonance effect stabilizes the the charge through the delocalization of the pi bonds. The resonance stabilization mainly occurs in the conjugated pi systems.
For example, phenol forms a strong hydrogen bonds than the nonaromatic alcohols as the 
dipole present in the hydroxyl group is being stabilized by the presence of the aromatic ring of phenol.
Thus the resonance effect of the hydroxyl group stabilizes the anionic intermediate.
D. microwaves, Ultraviolet, x-rays
Calcium chloride dehydrate (CaCl₂ · 2 H₂O) have a molar mass equal to 147 g/mol.
Explanation:
To calculate the molar mass of calcium chloride dehydrate (CaCl₂ · 2 H₂O) we use the following formula:
molar mass of CaCl₂ · 2 H₂O = atomic weight of Ca × 1 + atomic weight of Cl × 2 + atomic weight of H × 4 + atomic weight of O × 2
molar mass of CaCl₂ · 2 H₂O = 40 × 1 + 35.5 × 2 + 1 × 4 + 16 × 2
molar mass of CaCl₂ · 2 H₂O = 147 g/mol
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