Answer:
The answer is 0.0698 M
Explanation:
The concentration was prepared by a serial dilution method.
The formula for the preparation I M1V1 = M2V2
M1= the concentration of the stock solution = 0.171 M
V1= volume of the stock solution taken = 200 mL
M2 = the concentration produced
V2 = the volume of the solution produced = 940 mL
Substitute these values in the formula
0.171 × 200 = 490 × M2
34.2 = 490 × M2
Make M2 the subject of the formula
M2 = 34.2/490
M2 = 0.069795
M2 = 0.0698 M ( 3 s.f)
The concentration of the Chemist's working solution to 3 significant figures is 0.0698M
Answer: 31.55 g
Explanation:
- The mass number of Fluoride atom (F) = 18.99 g/mol, so mass number of fluorine gas (F2) = 37.98 g/mol.
- 1 mole of (F2) [which has 37.98 g/mol] contains Avogadro’s number of molecules (6.02×10^23 molecules),
so 1 mole of (F2) with 37.98 g/mol → 6.02×10^23 molecules.
- Using cross multiplication,
37.98 g/mol of (F2) → 6.02 ×10^23 molecules
? → 5.00 ×10^23 molecules
Hence the mass of 5.00×10^23 molecules of F2 = (37.98 × 5.00 × 10^23) / 6.02 ×10^23 = 31.55 g..
Ethanoic acid has the lowest vapour
The magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
Atomic radius decreases across the period but increases down the group. As more shells are added to the atom, the repulsion between electrons increases. Across the group, more electrons are added without increase in the number of shell hence atomic radius decreases across the period due to increase in the size of the nuclear charge. Therefore, the atomic radius of Li is larger than that of Be.
Ionization energy is a periodic trend that increases across the period but decreases down the group. Since the outermost electron is further from the nucleus due to screening of inner electrons, ionization energy decreases down the group. Across the period, the size of the nuclear charge increases hence ionization energy increases across the period.
For K, the second electron is removed from an inner shell which requires a very large amount of energy. In Ca, the second electron is removed from the valence shell which requires a lesser amount of energy. Therefore, the second ionization energy of K is greater than the second ionization energy of Ca.
The carbon to carbon bond in C2H4 is a double bond which has a greater bond enthalpy than the single bond in C2H6. As such, the carbon to carbon bond in C2H4 has a greater bond energy than the carbon to carbon bond in C2H6.
The boiling point of Cl2 is lower than the boiling point of Br2 because Br2 is larger than Cl2 hence the magnitude of dispersion forces in Br2 is greater than the magnitude of dispersion forces in Cl2.
Learn more: brainly.com/question/11155928
The formula for Hexafluoride is F6S.
