Carlota does 2000 J of work on a machine. The machine does 500 J of work. What is the efficiency of the machine?

What is the wavelength of radiation with a frequency of 1.50x10^13 hz?

stiks02 [169]

Π = c/ f
π = 3×10^8 / 1.5×10^13
π = 3÷1.5 ×10^(8-13)
π = 2×10^-5 m

7 0

4 years ago

1) Subatomic particles called muons can be created in the upper atmosphere by collisions of cosmic rays (energetic particles com

Vsevolod [243]

Answer and explanation:

A.

Muon travelled straight down towards the earth. Therefore the tree moves up in the rest frame of muon (option a)

B.

In muon rest frame it travels Zero meters

C.

Distance, d = Velocity, v * Time, s

$where, v = 0.9c = 0.9 \times 8 \times 10^8 , s = 2.2 \mu s$

$d = 0.9 \times 3 \times 10^8 \times 2.2 \times 10^{-6}\\\\d = 594m$

D.

Distance from the top of the mountain to the tree is the same as the distance travelled by the tree in the muons rest frame

that is same as in part C which is 594m

E.

Using lorentz contraction

In the rest frame of someone standing on the mountain

the distance is given by

$d' = \frac{d}{\gamma} = d\sqrt{1 - \frac{v^2}{c^2}}, where, \frac{1}{\gamma}= \sqrt{1 - \frac{v^2}{c^2}}$

$d' = 594\sqrt{1 - \frac{(0.9c)^2}{c^2}}$

$d' = 594\sqrt{1 - 0.81}$

$d' = 594 \times 0.4359$

d' = 258.92m

F.

in the rest frame of someone standing on the mountain,

muon moves straight down

3 0

4 years ago

A particle with kinetic energy equal to 282 J has a momentum of magnitude 26.4 kg · m/s. Calculate the speed (in m/s) and the ma

masha68 [24]

Answer:

$v=21.36\,\,\frac{m}{s}\\$

$m=1.2357\,\,kg$

Explanation:

Recall the formula for linear momentum (p):

$p = m\,v$ which in our case equals 26.4 kg m/s

and notice that the kinetic energy can be written in terms of the linear momentum (p) as shown below:

$K=\frac{1}{2} m\,v^2=\frac{1}{2} \frac{m^2\,v^2}{m} =\frac{1}{2}\frac{(m\,v)^2}{m} =\frac{p^2}{2\,m}$

Then, we can solve for the mass (m) given the information we have on the kinetic energy and momentum of the particle:

$K=\frac{p^2}{2\,m}\\282=\frac{26.4^2}{2\,m}\\m=\frac{26.4^2}{2\,(282)}\,kg\\m=1.2357\,\,kg$

Now by knowing the particle's mass, we use the momentum formula to find its speed:

$p=m\,v\\26.4=1.2357\,v\\v=\frac{26.4}{1.2357} \,\frac{m}{s} \\v=21.36\,\,\frac{m}{s}$

4 0

3 years ago

A liquid with a mass of 75 g is at its boiling point. It completely boils off when AQ = 15000000) of heat energy is added to it.

aev [14]

Answer:

2 × 10⁸J/kg

Explanation:

Specific latent heat of vaporization (steam) is the quantity of heat required or needed to change a unit of mass of liquid to gaseous state at constant temperature (boiling point) and pressure.

It can be calculated mathematically using,

Q = mL

Where, Q = quantity of heat

m= mass in kg

L = specific latent heat (J/kg)

Therefore,from the question

Q= 15000000J

mass (m) = 75g = 75/1000 kg = 0.075kg

Q = mL

L = Q/m

L = 15000000 ÷ 0.075

L= 200000000J/kg

L = 2 × 10⁸J/kg

I hope this was helpful, please mark as brainliest

8 0

3 years ago

ASAP 1-5 question plzz helppp, mark Brainliest if you answer all 5 questions

podryga [215]

Answer:

a,b,d,b, false

Explanation:

7 0

3 years ago

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