Answer:
A. W = 6875.0 J.
B. W = -14264.6 J.
Explanation:
A. The work done by the rider can be calculated by using the following equation:

Where:
: is the force done by the rider = 25 N
d: is the distance = 275 m
θ: is the angle between the applied force and the distance
Since the applied force is in the same direction of the motion, the angle is zero.

Hence, the rider does a work of 6875.0 J on the bike.
B. The work done by the force of gravity on the bike is the following:
The force of gravity is given by the weight of the bike.
And the angle between the force of gravity and the direction of motion is 180°.
The minus sign is because the force of gravity is in the opposite direction to the motion direction.
Therefore, the magnitude of the work done by the force of gravity on the bike is 14264.6 J.
I hope it helps you!
Answer:
<em>Sonogram </em><em>is </em><em>a </em><em>medical </em><em>image </em><em>produced </em><em>by </em><em>ultrasound </em><em>echo. </em>
<em>It </em><em>is </em><em>used </em><em>to </em><em>help</em><em> </em><em>diagnose </em><em>causes </em><em>of </em><em>pain </em><em>and </em><em>swelling</em><em>. </em>
Answer:
Q = 116.8 J
Explanation:
Here given that the temperature of 1 L hydrogen is increased by 90 degree C at constant pressure condition.
So here we will have

here we know that
n = number of moles


for ideal diatomic gas molar specific heat capacity at constant pressure is given as

now we have


Answer:
Minimum distance needed to move one of the mirrors = 125 nm
Explanation:
Constructive interference occurs when the maxima (trough or crest) of two waves that are in phase add together so that the amplitude of the resulting wave is equal to the sum of the individual amplitudes.
Destructive interference occurs when the maxima (trough or crest) of two waves that are out of phase by 180⁰ or half a wavelength combine to produce a smaller amplitude than the individual amplitudes that combine. It can even produce a wave of zero amplitude.
Since the spot of constructive interference has been changed to destructive interference, Path difference = Wavelength/2
Path difference = 500nm/2 = 250 nm
Path difference = 250 * 10⁻⁹ m
Since there are two interferometer's mirrors and only one is moved, the minimum distance will be a half of the path difference.
That is, minimum distance = (path difference)/2
Minimum distance = (250 * 10⁻⁹)/2
Minimum distance = 125 * 10⁻⁹ m
Minimum distance = 125 nm
Answer:
the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94
Explanation:
Given that ;
the top speed of Cheetahs is almost 60 mph
In cornering abilities ; the maximum centripetal acceleration of a cheetah was measured to be = 19 m/s^2
The objective of this question is to determine the what minimum value of the coefficient of static friction between the ground and the cheetah's feet is necessary to provide this acceleration?
From the knowledge of Newton's Law;
we knew that ;
Force F = mass m × acceleration a
Also;
The net force
= frictional force 
so we can say that;
m×a = 
where;
the coefficient of static friction
is:



= 1.94
Hence; the minimum value of the coefficient of static friction between the ground and the cheetah's feet is 1.94