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Margaret [11]
3 years ago
5

Can someone help me with the question in the image. if correct i will mark as brainliest

Chemistry
1 answer:
shtirl [24]3 years ago
6 0

Answer: <em>tree rings- kind of plans, rain fall- ice, </em>

Explanation: it goes together

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A sample of lead has a density of 11.3 g/cm3 and a mass of 123 grams, what is the volume of the sample?
SVEN [57.7K]

Answer:

The answer is

<h2>11.18 cm³</h2>

Explanation:

The volume of a substance when given the density and mass can be found by using the formula

volume =  \frac{mass}{density} \\

From the question

mass = 123 g

density = 11.3 g/cm³

The volume is

volume =  \frac{123}{11.3}   \\  = 11.18181818...

We have the final answer as

<h3>11.18 cm³</h3>

Hope this helps you

3 0
3 years ago
Let's say that you were given the following
mezya [45]

Answer:

V2~0.4839M

Explanation:

We're going to use Boyles law to answer the question.

Boyle's law:

P1V1=P2V2

P1=151mmHg

P2=166mmHg

V1=0.532L

V2=?

V2=(P1 x V1)/P2

V2=(151 x 0.532)/166

V2~0.4839M

Hope it helps:)

8 0
2 years ago
How would I find the number of protons, neutrons and electrons when I only have the atomic number and atom (assignment says assu
coldgirl [10]

Explanation:

Atomic number , protons and electrons have the same value / their value is same .

But for the neutron there is no specific technique. You have to remember the neutrons of every element

8 0
2 years ago
What did Thomson’s model of the atom include that Dalton’s model did not have?
Allushta [10]
Thomson's model included Protons and Electrons. His model is referred to as 'Plum Pudding' because of it.
6 0
3 years ago
Read 2 more answers
You weigh out 0.1183 g of a complex salt to analyze for the percentage of cyanide ion in your complex salt. After dissolving the
Stels [109]

Answer:

25.35%

Explanation:

Again let me restate the the equation of the reaction;

H2O (ℓ) + 2 MnO4 - (aq) + 3 CN- (aq) → 2 MnO2 (s) + 3 CNO- (aq) + 2 OH- (aq)

Amount of potassium permanganate  reacted = 10.2/1000 * 0.08035 = 8.1957 * 10^-4 moles

If 2 moles of MnO4 - reacts with 3 moles of CN-

8.1957 * 10^-4 moles of MnO4 - reacts with 8.1957 * 10^-4 * 3/2

= 1.229 * 10^-3 moles of CN-

Mass of CN- reacted = 1.229 * 10^-3 moles of CN- * 26.02 g/mol

= 0.03 g

Hence, percentage of the cyanide = 0.03 g/0.1183 g * 100

= 25.35%

8 0
3 years ago
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