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natulia [17]
3 years ago
14

What will occurs during electrolysis of dilute sulphuric acid​

Chemistry
1 answer:
Alexxandr [17]3 years ago
7 0

Answer:

In the electrolysis of dilute sulfuric acid, which electrolysis in aqueous solution to form hydrogen ions, H⁺, and sulfur IV ions SO₄²⁻ in the presence of H⁺ and OH⁻ ions from the water molecules

At the anode

The anode, positive electrode, attracts the negative OH⁻ and SO₄²⁻ ions where the OH⁻ gives up electrons to form water molecules and oxygen as follows;

4OH⁻ → 2H₂O + O₂ + 4e⁻

At the cathode

The positive H⁺ ions from the water molecules and the acid are attracted to the cathode where they combine with 2 electrons to form hydrogen gas as follows;

2e⁻ + 2H⁺ → H₂ (gas)

Explanation:

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Write an equation for the reaction that takes place in a luminous flame assuming the laboratory gas is Butane
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4 0
2 years ago
Methanol, ethanol, and n-propanol are three common alcohols. When 1.00 g of n-propanol (C3H7OH)is burned in air, -33.4 kJ of hea
Inga [223]

Answer : The heat of combustion of n-propanol is 0.554 kJ/mol

Explanation :

First we have to calculate the moles of n-propanol.

\text{Moles of n-propanol}=\frac{\text{Mass of n-propanol}}{\text{Molar mass of n-propanol}}

Molar mass of n-propanol = 60.09 g/mole

\text{Moles of n-propanol}=\frac{1.00g}{60.09g/mole}=0.0166mole

Now we have to calculate the heat of combustion of n-propanol.

As, 0.0166 mole of n-propanol liberated heat of combustion = -33.4 kJ

So, 1 mole of n-propanol liberated heat of combustion = 0.0166 × (-33.4 kJ)

                                                                                           = 0.554 kJ/mol

Therefore, the heat of combustion of n-propanol is 0.554 kJ/mol

5 0
3 years ago
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