I divided the volume by a 1000 because it must be in litres, but it wont make any difference because they will cancel out, but you must always convert it to L or dm3 unless it says in the question something else.
Answer:
When water freezes and turns into ice, it releases latent heat. Then, the ice that builds up on the plant will insulate it from the colder surrounding air temperatures. Because of this, some growers choose to spray their crop with water before the freeze occurs.
Explanation:
Answer:
The solute that is most likely soluble in hexane is S₈
Explanation:
S₈ is a non-polar solute that exhibits the same characteristics and properties as hexane. Following the common principle "like dissolves like"; polar compounds will be soluble in polar solvents while non-polar compounds will be soluble in non-polar solvents. As such, since S₈ is non-polar, then it will be soluble in hexane.
Answer:
About 0.652
Explanation:
Because the reaction is balanced, we can go straight to the next step. The molar mass of potassium is about 39.098, while the molar mass of hydrogen gas is 2 and the molar mass of water is 18. Therefore, 25.5g of potassium would be about 0.652 moles, and 220 grams of water would be about 12.222 moles, making potassium the limiting reactant. Since there is a single unit of each compound on both sides of the equation, there would be an equal amount of moles of potassium and hydrogen, and therefore about 0.652 moles of hydrogen gas would be produced. Hope this helps!
Answer:
This will be the balanced half reaction:
NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)
Explanation:
In acidic medium, the redox balance has to be done as this way.
As it is an oxidation, we know that oxidation state has increased.
NO₂(g) → NO₃⁻(aq) + 1 e⁻
Nitrogen in NO₂ acts with +4; in the nitrate, N acts with +5
The nitrogen has released 1 electron.
As we are in acidic medium, we must complete with water, in the same side, as we have less oxygens and in the opposite side, with protons to balance the H. This will be the balanced half reaction:
NO₂(g) + H₂O (l) → NO₃⁻(aq) + 1 e⁻ + 2H⁺ (aq)