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Katyanochek1 [597]
3 years ago
5

The size of your pool cover distance or area

Mathematics
2 answers:
dybincka [34]3 years ago
3 0

Answer:

You solve this question

Step-by-step explanation:

Area = To work out the area of a square or rectangle, multiply its height by its width. If the height and width are in cm, the area is shown in cm².

Distance = It a numerical measurement of how far apart objects or points are.

Anarel [89]3 years ago
3 0

Answer:

My pool's maximum depth: 6ft

My pool's full width: 10ft

My pool's full length: 12ft

(yea, it's pretty big!)

How do I find the area of my pool now?

First, let's start with the distance covered by the pool (area)

We can find that by just doing 10x12, which is 120

So, my pool's distance is 120ft²

EXTRA:

Now, the VOLUME of my pool...

we can find it by doing 6x10x12

6x10=60

6x12=72

60x12=720

So, my pool's VOLUME is 720ft.²

Thanks!

Answered by: FieryAnswererGT

#learnwithbrainly

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The inequality that represents the constraint is: 12x + 6y \le 20

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From the question, we have:

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A cylindrical bucket is being filled with paint at a rate of 4 cm3 per minute. How fast is the level rising when the bucket star
andre [41]

Answer:

Therefore,the level of paint is rising when the bucket starts to overflow at a rate  \frac{1}{100\pi} cm per minute.

Step-by-step explanation:

Given that, at a rate 4 cm³ per minute,a cylinder bucket is being filled with paint

It means the change of volume of paint in the cylinder is 4 cm³ per minutes.

i.e \frac{dV}{dt}= 4 cm³ per minutes.

The radius of the cylinder is 20 cm which is constant with respect to time.

But the level of paint is rising with respect to time.

Let the level of paint be h at a time t.

The volume of the paint at a time t is

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\Rightarrow \frac{dh}{dt}=\frac{4}{400\pi}

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\left \frac{dh}{dt}\right|_{h=70}=\frac{1}{100\pi}

Therefore, the level of paint is rising when the bucket starts to overflow at a rate \frac{1}{100\pi} cm per minute.

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