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Neporo4naja [7]

2 years ago

7

A digital clock displays military time in hh:mm format. Find the probability that the number made up of the first two digits on

the clock is less than 25.

1 answer:

attashe74 [19]2 years ago

4 0

Answer:

0

Step-by-step explanation:

there is a maximum of 24 hours in a day and the highest we can have is 23:59.. it's impossible for it to be the 25th hour in a day

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1/4 divided by 2/6 in simplest form

Nuetrik [128]

Answer:

1/4*6/2=6/8

3/4

Step-by-step explanation:

3 0

6 months ago

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The winner of a raffle will receive three/fourths of the money raised from a raffle ticket sales the raffle raised $530.40 how m

Roman55 [17]

It is 397.8 bc if u make 530.4 a fraction = 530.4/1 then u just multiply it by 3/4 u will get 1591.2/4 then u simply reduce it by dividing ( top in , bottom out ) and u get 397.8

7 0

2 years ago

Where t is the number of years since 1997 and y is the number of camera phones shipped(in millions). How many camera phones were

Furkat [3]

Not enough information if that is an option

3 0

3 years ago

Find the solution to t - (-2) = 6.

Alex_Xolod [135]

<span>t - (-2) = 6
t + 2 = 6
subtract 2 to both sides
t + 2 - 2 = 6 -2
simplify
t = 4</span>

6 0

2 years ago

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Mathematics 13 don’t understand

UNO [17]

Answer:

1/6^3

Step-by-step explanation:

The applicable rules of exponents are ...

a^-b = 1/a^b

(a^b)(a^c) = a^(b+c)

__

Your expression can be simplified as follows:

$\dfrac{6^{-5}}{6^{-2}}=\dfrac{1}{(6^{-2})(6^5)}=\dfrac{1}{6^{-2+5}}=\boxed{\dfrac{1}{6^3}}$

_____

<em>Additional comment</em>

If you think of an exponent as signifying repeated multiplication, the rules of exponents may be easier to remember. The exponent tells you how many times the base is a factor in the product.

Consider multiplication:

$(x\cdot x\cdot x)\cdot(x\cdot x)=x^3\cdot x^2=x^{3+2}=x^5\\\\(x\cdot x\cdot x)\cdot(x\cdot x\cdot x)=(x^3)^2=x^{3\cdot2}=x^6$

Consider division:

$\dfrac{x\cdot x\cdot x}{x\cdot x}=x\quad\Longleftrightarrow\quad\dfrac{x^3}{x^2}=x^{3-2}=x^1\\\\\dfrac{x\cdot x}{x\cdot x\cdot x}=\dfrac{1}{x}\quad\Longleftrightarrow\quad\dfrac{x^2}{x^3}=x^{2-3}=x^{-1}$

This may help you see that a positive exponent in the denominator is equivalent to a negative exponent in the numerator (and vice versa).

6 0

2 years ago