Hello!
log₃(x) + log₃(x - 6) = log₃(7) <=>
<=> log₃(x * (x - 6)) = log₃(7) <=>
<=> log₃(x² - 6x) = log₃(7) <=>
<=> x² - 6x = 7 <=>
<=> x² - 6x - 7 = 0 <=>
<=> x² + x - 7x - 7 = 0 <=>
<=> x * (x + 1) - 7 * (x + 1) = 0 <=>
<=> (x + 1) * (x - 7) = 0 <=>
<=> x + 1 = 0 and x - 7 = 0 <=>
<=> x = -1 and x = 7, x ∈ { 6; +∞ } <=>
<=> x = 7
Good luck! :)
We can simplify by 7
28/7 = 4
35/7 = 5
Answer- 4/5
Answer:
C. 3
Step-by-step explanation:
You know the angle sum is ...
∠FGT +∠TGH = ∠FGH
You can use this relation with the given values to find x.
90 + (8x +4) = 39x +1
93 = 31x . . . . . . . . . . . . . add -1-8x, collect terms
3 = x . . . . . . . . . . . . . . . . divide by 31
the student has left 75 because if you add 5 and 70 it gives you $75 that's how much the student had left.
sorry my brain is the size of a ant
