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3 years ago

Integers that satisfy the inequality -9 < x -3 < 1?

Mathematics

1 answer:

Leni [432]3 years ago

7 0

Answer:

see explanation

Step-by-step explanation:

Given

- 9 < x - 3 < 1 ( add 3 to each interval )

- 6 < x < 4

Thus integer values which satisfy the inequality are

x = - 5, - 4, - 3, - 2, - 1, 0, 1, 2, 3

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4 years ago

Danielle can type at a rate of 55 words per minute. How many words can she type in four and a half minutes?

Romashka [77]

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3 years ago

Find the value of the missing side-Use SOH CAH TOA

Vanyuwa [196]

Answer:

4.04 (idk how you want it rounded)

Step-by-step explanation:

1) Use TOA

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3 years ago

Read 2 more answers

HELP ⚠⚠⚠ MARKING BRAINLIEST, IF UR CONFUSED, I NEED HELP WITH QUESTION 9 BUT QUESTION 8 IS RELATED TO IT ⚠⚠⚠

4vir4ik [10]

Answer:

John has a sheet of paper that is 8 feet long. He cuts the length of paper into eighths, and then cuts the length of each of these $\frac{1}{8}$ pieces into fourths. How many pieces does he have? How many inches long is each piece?

Step-by-step explanation:

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3 years ago

A uniform 41.0 kg scaffold of length 6.6 m is supported by two light cables, as shown below. A 74.0 kg painter stands 1.0 m from

Nimfa-mama [501]

Step-by-step explanation:

Let

$m_p$ = mass of the painter

$m_s$ = mass of the scaffold

$m_e$ = mass of the equipment

$T$ = tension in the cables

In order for this scaffold to remain in equilibrium, the net force and torque on it must be zero. The net force acting on the scaffold can be written as

$3T = (m_p + m_s + m_e)g\:\:\:\:\:\:\:(1)$

Set this aside and let's look at the net torque on the scaffold. Assume the counterclockwise direction to be the positive direction for the rotation. The pivot point is chosen so that one of the unknown quantities is eliminated. Let's choose our pivot point to be the location of $m_e$ . The net torque on the scaffold is then

$T(1.4\:\text{m}) + m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m}) - 2T(5.2\:\text{m}) = 0$

Solving for T,

$9T = m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})$

$T = \frac{1}{9}[m_sg(1.9\:\text{m}) + m_pg(4.2\:\text{m})]$

$\:\:\:\:= 423.3\:\text{N}$

To solve for the the mass of the equipment $m_e$ , use the value for T into Eqn(1):

$m_e = \dfrac{3T - (m_p + m_s)g}{g} = 14.6\:\text{kg}$

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3 years ago