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iogann1982 [59]
2 years ago
5

Solution of the system of inequalities

Mathematics
1 answer:
Agata [3.3K]2 years ago
5 0

Answer:

Step-by-step explanation:

(0,-1) is not part of the solution because:

It is not in the solution region and

the bottom line is not inclusive so it does not count.

Any points in the shaded region are solutions. Since (0,-1) is not in the shaded region it is not a solution.

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2 years ago
Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated
Illusion [34]

Answer:

x=-2,0,3

Step-by-step explanation:

We have been given a function f(x)=15x^3-15x^2-90x. We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

15x^3-15x^2-90x=0

Now, we will factor our equation. We can see that all terms of our equation a common factor that is 15x.

Upon factoring out 15x, we will get:

15x(x^2-x-6)=0

Now, we will split the middle term of our equation into parts, whose sum is -1 and whose product is -6. We know such two numbers are -3\text{ and }2.

15x(x^2-3x+2x-6)=0

15x((x^2-3x)+(2x-6))=0

15x(x(x-3)+2(x-3))=0

15x(x-3)(x+2)=0

Now, we will use zero product property to find the zeros of our given function.

15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0

15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0

\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0

x=0\text{ (or) }x=3\text{ (or) }x=-2

Therefore, the zeros of our given function are x=-2,0,3.

7 0
3 years ago
Help asap I will give u huge amount of brainly points
Minchanka [31]

Answer:

\boxed{\sf -\dfrac{5}{8}}

Use BODMAS rule,

where:

  • brackets
  • order
  • division
  • multiplication
  • addition
  • subtraction

Given expression:

\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{4} \right)^2]

simplify exponent

\rightarrow \sf -\dfrac{1}{5} \times [\:4-14\times\left(\dfrac{1}{16} \right)]

\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{14}{16}]

\rightarrow \sf -\dfrac{1}{5} \times [\:4-\(\dfrac{7}{8}]

\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{32}{8} -\(\dfrac{7}{8}]

\rightarrow \sf -\dfrac{1}{5} \times [\:\dfrac{25}{8}]

multiply fractions

\rightarrow \sf -\dfrac{25}{40}

\rightarrow \sf -\dfrac{5}{8}

8 0
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the diamiter is the two out side numbers minused by 3.14

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A researcher computes r = 0.45 using a sample of 18 participants. Is this Pearson correlation coefficient significant for a two-
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Answer with explanation:

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Sample size : n=18

Degree of freedom : df=n-2=18-2=16

Now, the critical value for Pearson correlation coefficient  for a two-tailed test at a .05 level of significance will be :

r_c=0.468   ( by critical correlation coefficient table)

Since , r>r_c i.e. 0.45>0.468 , then we say that his Pearson correlation coefficient is not significant for a two-tailed test at a .05 level of significance.

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2 years ago
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