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grandymaker [24]
3 years ago
14

I need very urgent help with this

Mathematics
2 answers:
GrogVix [38]3 years ago
7 0

Answer:

Yep the dude is right

Step-by-step explanation:

Svetlanka [38]3 years ago
6 0
P(-5) = (-5)³ - 6(-5)² - 7(-5) + 60

p(-5) = -125 - 6(25) - (-35) + 60

p(-5) = -125 - 150 + 35 + 60

p(-5) = -275 + 95

p (-5) = -180


so is x + 5 a factor of polynomial ( NO) because when make a substitution by -5 the answer will not be 0
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The expression 5 +9y?
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Can you repost with the full question?
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Answer:

Solving the expression  \frac{\sqrt[3]{7} }{\sqrt[5]{7} } we get \mathbf{7^{\frac{2}{15}}}

Option D is correct option.

Step-by-step explanation:

We need to solve the expression: \frac{\sqrt[3]{7} }{\sqrt[5]{7} }

We know that

\sqrt[3]{x}=x^{\frac{1}{3} and \sqrt[5]{x}=x^{\frac{1}{5}

<u>Using above rule:</u>

<u />\frac{\sqrt[3]{7} }{\sqrt[5]{7} }\\=\frac{7^{\frac{1}{3}}}{7^{\frac{1}{5}}}<u />

Now, we know the exponent rule if bases are same and divided then exponents are subtracted i.e:  \frac{a^m}{a^n}=a^{m-n}<u />

Using the exponent rule

=7^{\frac{1}{3}-\frac{1}{5}  }\\Simplifying\:exponents\\=7^{\frac{5-3}{15}}\\=7^{\frac{1*5-1*3}{15}}\\=7^{\frac{2}{15}}

So, solving the expression  \frac{\sqrt[3]{7} }{\sqrt[5]{7} } we get \mathbf{7^{\frac{2}{15}}}

Option D is correct option.

8 0
3 years ago
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Answer:

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Step-by-step explanation:

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