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Otrada [13]
3 years ago
8

A couple plans to have 3 children. Assuming the probability of having either a boy or a girl is 50%, what is the probability the

y will have at least 1 girl?
Group of answer choices

0.875

0.125

0.375

0.75
Mathematics
1 answer:
Stels [109]3 years ago
4 0

Answer:

0.375

Step-by-step explanation:

The probability of having at least one girl out of 3 children can be calculated as;

P(1 girl, 2 boys) or P(2 girls, 1 boy) or P(3 girls)

Since the P(b) = P(g) = 1/2

Then the probability at any point in time is 1/2 * 1/2 * 1/2 = 1/8

So we have ;

1/8 + 1/8 + 1/8 = 3/8 = 0.375

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What is the domain of the function y= square root x - 5 - 1
IrinaK [193]

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Step-by-step explanation:

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Answer:

The responses to the given question can be defined as follows:

Step-by-step explanation:

Please find the complete question in the attached file.

Day \ \ \ \ \ \ \ \ \ \ Period \ \ \ \ \ \ \ \ \ \ Demand \ \ \ \ \ \ \ \ \ \ 5-period moving average

1 \ \ \ \ \ \ \ \ \ \ \  Morning \ \ \ \ \ \ \ \ \ \ \ 37 \\\\

            Afternoon \ \ \ \ \ \ \ \ \ \ \ 25  \\\\ Evening \ \ \ \ \ \ \ \ \ \ \  9

2 \ \ \ \ \ \ \ \ \ \ \  Morning \ \ \ \ \ \ \ \ \ \ \48 \\\\

           Afternoon\ \ \ \ \ \ \ \ \ \ \ 28 \\\\

            Evening \ \ \ \ \ \ \ \ \ \ \ 14 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  29.4 \\\\

3 \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ 53 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  24.8\\\\

              Afternoon \ \ \ \ \ \ \ \ \ \ \ 33 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  30.4\\\\Evening \ \ \ \ \ \ \ \ \ \ \ 17 \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ 35.2\\\\

4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ Morning \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \  \ \ \ \ 29\\\\

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