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serg [7]
3 years ago
9

Does somene know easy if u know it

Mathematics
2 answers:
Levart [38]3 years ago
8 0

Answer:

valid

Step-by-step explanation:

because area of a square if found by A=a^2

(this can also be length times height since a square has all 4 equal sides)

3*3=9

Nookie1986 [14]3 years ago
4 0

Answer:

valid bc in a square all the sides are the same.

Step-by-step explanation:

so side 1 and side 2 both equal 3. 3×3=9

so the answer is valid

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Is the ordered pair
FrozenT [24]

Answer:

no, because for x=-3, y would have to be -31

Step-by-step explanation:

boy oh boy (or girl oh girl) - you wrote this in a horrible, horrible format.

I can only guess what your problem and the fitting answer would be.

y = -2×x^2 + 3×x - 4

-4 = -2×(-3)^2 + 3×(-3) - 4

-4 = -2×9 - 9 - 4

-4 = -18 - 9 - 4

-4 = -31

and that is wrong. for (-3,-4) to be on the graph of the function, y would have to be -4 when using x=-3 in the function. but y = -31 for x= -3.

8 0
3 years ago
find the equation of the circle where (-9,4),(-2,5),(-8,-3),(-1,-2) are the vertices of an inscribed square.
solniwko [45]
Check the picture below, so, that'd be the square inscribed in the circle.

so... hmm the diagonals for the square are the diameter of the circle, and keep in mind that the radius of a circle is half the diameter, so let's find the diameter.

\bf \textit{distance between 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
%  distance value
d = \sqrt{({{ x_2}}-{{ x_1}})^2 + ({{ y_2}}-{{ y_1}})^2}
\\\\\\
\stackrel{diameter}{d}=\sqrt{[-8-(-2)]^2+[-3-5]^2}
\\\\\\
d=\sqrt{(-8+2)^2+(-3-5)^2}\implies d=\sqrt{(-6)^2+(-8)^2}
\\\\\\
d=\sqrt{36+64}\implies d=\sqrt{100}\implies d=10

that means the radius r = 5.

now, what's the center?  well, the Midpoint of the diagonals, is really the center of the circle, let's check,

\bf \textit{middle point of 2 points}\\ \quad \\
\begin{array}{lllll}
&x_1&y_1&x_2&y_2\\
%  (a,b)
&({{ -2}}\quad ,&{{ 5}})\quad 
%  (c,d)
&({{ -8}}\quad ,&{{ -3}})
\end{array}\qquad 
\left(\cfrac{{{ x_2}} + {{ x_1}}}{2}\quad ,\quad \cfrac{{{ y_2}} + {{ y_1}}}{2} \right)
\\\\\\
\left( \cfrac{-8-2}{2}~,~\cfrac{-3+5}{2} \right)\implies (-5~,~1)

so, now we know the center coordinates and the radius, let's plug them in,

\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}\\
&-5&1&5
\end{array}
\\\\\\\
[x-(-5)]^2-[y-1]^2=5^2\implies (x+5)^2-(y-1)^2=25

8 0
3 years ago
Please help please i dont know how to do it I need to get my grades up asap
bearhunter [10]

Answer:

Well if you need help with graphing, there's a website named Desmos Graphing calculator. If you want to get your grades up, listen to some music then do the easy stuff. I dont know any websites from the top of my head :p

Step-by-step explanation:

6 0
3 years ago
The Science Club went on a two-day field trip. The first day the members paid $50 for transportation plus
Anastasy [175]

Answer:

145 + 33n

Step-by-step explanation:

Let

n = number of members in the club

Day 1:

Cost = 50 + 18n

Day 2:

Cost = 95 + 15n

Total cost two-day field trip = day 1 + day 2

= (50 + 18n) + (95 + 15n)

= 50 + 18n + 95 + 15n

= 145 + 33n

Total cost two-day field trip = 145 + 33n

An expression that represents the total cost in dollars for two days for the n members of the club is given by 145 + 33n

4 0
2 years ago
20 POINTS PLEASE HELP ASAP
Brut [27]

Answer:

A. If we consider two right triangles one Δ ABD and Δ BCE, where D(2,100) and E(1,60) points

B. From the graph, it is clear that the initial value of the graph is 60 m and it represents the initial position of the shark i.e. at t = 0 min, the shark was at a depth of 60 m from the water surface.

 

The slope of the graph is 40 means the rate of change of distance from the Ocean surface of the shark with respect to time in minutes will be 40 m per min.

Step-by-step explanation:

6 0
2 years ago
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