Answer:
11963.43 N
Explanation:
From the question given above, the following data were obtained:
Mass of the earth (Mₑ) = 5.97x10²⁴ Kg
Mass of satellite (Mₛ) = 1300 Kg
Radius of the earth (R) = 6378 km
Distance between the earth and satellite (r) = R + 200 Km = 6378 + 200 = 6578 Km
Force of gravity (F) =?
Next, we shall convert 6578 Km to m. This can be obtained as follow:
1 Km = 1000 m
Therefore,
6578 Km = 6578 Km × 1000 m / 1 Km
6578 Km = 6578000 m
Finally, we shall determine the force of gravity. This can be obtained as follow:
Mass of the earth (Mₑ) = 5.97x10²⁴ Kg
Mass of satellite (Mₛ) = 1300 Kg
Distance apart (r) = 6578000 m
Gravitational constant (G) = 6.67×10¯¹¹ Nm²/Kg²
Force of gravity (F) =?
F = GMₑMₛ / r²
F = (6.67×10¯¹¹ × 5.97x10²⁴ × 1300) / (6578000)²
F = 11963.43 N
Therefore, the force of gravity on the scientific satellite 11963.43 N
