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3 years ago

Help me please!!!!!..............

Physics

1 answer:

qaws [65]3 years ago

6 0

Answer:

<em>The car took 3 hours to travel 180 miles</em>

Explanation:

<u>Constant Speed Motion</u>

An object travels at constant speed if the ratio of the distance traveled by the time taken is constant.

Expressed in a simple equation, we have:

$\displaystyle v=\frac{d}{t}$

Where

v = Speed of the object

d = Distance traveled

t = Time taken to travel d.

From the equation above, we can solve for t:

$\displaystyle t=\frac{d}{v}$

The car travels at v=60 mi/h for a distance of d=180 miles. The time taken is:

$\displaystyle t=\frac{180\ mi}{60\ mi/h}$

t = 3 hours

The car took 3 hours to travel 180 miles

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A team of astronauts is on a mission to land on and explore a large asteroid. In addition to collecting samples and performing e

Blizzard [7]

<h2>Answer: 117.626m/s</h2>

Explanation:

The escape velocity $V_{esc}$ is given by the following equation:

$V_{esc}=\sqrt{\frac{2GM}{R}}$ (1)

Where:

$G$ is the Gravitational Constant and its value is $6.674(10)^{-11}\frac{m^{3}}{kgs^{2}}$

$M$ is the mass of the asteroid

$R$ is the radius of the asteroid

On the other hand, we know the density of the asteroid is $\rho=3.84(10)^{8}g/m^{3}$ and its volume is $V=2.17(10)^{12}m^{3}$ .

The density of a body is given by:

$\rho=\frac{M}{V}$ (2)

Finding $M$ :

$M=\rhoV=(3.84(10)^{8} g/m^{3})(2.17(10)^{12}m^{3})$ (3)

$M=8.33(10)^{20}g=8.33(10)^{17}kg$ (4) This is the mass of the spherical asteroid

In addition, we know the volume of a sphere is given by the following formula:

$V=\frac{4}{3}\piR^{3}$ (5)

Finding $R$ :

$R=\sqrt[3]{\frac{3V}{4\pi}}$ (6)

$R=\sqrt[3]{\frac{3(2.17(10)^{12}m^{3})}{4\pi}}$ (7)

$R=8031.38m$ (8) This is the radius of the asteroid

Now we have all the necessary elements to calculate the escape velocity from (1):

$V_{esc}=\sqrt{\frac{2(6.674(10)^{-11}\frac{m^{3}}{kgs^{2}})(8.33(10)^{17}kg)}{8031.38m}}$ (9)

Finally:

$V_{esc}=117.626m/s$ This is the minimum initial speed the rocks need to be thrown in order for them never return back to the asteroid.

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3 years ago

Find the mass of a copper block with heat capacity 50j/kg,(specific heat capacity of copper=400j/kg)

kirza4 [7]

−1
C
−1
and L
f

=3.5×10
5
Jkg
−1

Mass of copper block m=2kg
Heat released by the copper block is equal to the heat gained by the ice to melt.
Let the mass of the ice melted be M.
Change in temperature of copper block ΔT=500−0=500
o
C
∴ mS(ΔT)=ML
f

Or 2×400×500=M×3.5×10
5

⟹ M=1.14kg

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Answer:

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