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Salsk061 [2.6K]
3 years ago
14

A 0.10 kg stone is thrown from the edge of an ocean cliff with an initial speed

Physics
1 answer:
AfilCa [17]3 years ago
6 0

Answer:

79.20 joule

Explanation:

1.

A 0.10kg stone is thrown from the edge of an ocean cliff with an initial speed of 21m/s. When it strikes the water below, it is traveling at 45m/s. What is the change in kinetic energy of the stone?

ΔEk = m/2*(V2^2-V1^2) = 0.05*(45^2-21^2) = 79.20 joule

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3 years ago
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Answer:

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Explanation:

In order to calculate the angular velocity of the second wheel, you use the following formula:

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3 years ago
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In short, Your Answer would be 2704 Joules

Hope this helps!
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