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Nezavi [6.7K]
2 years ago
5

Use inverse operations to solve the equation. −4x = 52

Mathematics
2 answers:
elena-14-01-66 [18.8K]2 years ago
5 0

Answer:

x=-13

Step-by-step explanation:

divide 52 by -4 to get x=-13

scZoUnD [109]2 years ago
4 0

Answer:

x = -13

Step-by-step explanation:

−4x = 52

Divide both sides by -4 to isolate the variable

-4x/-4 = 52/-4

x = - 13

Check:

Substitution

-4 (-13) = 52

52 = 52

* 2 negatives make a positive

Hope this helped!

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Write the equation of the line in slope-intercept form using y=mx+b​
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The slope is positive thus the line is increasing or rising from left to right, but passing through the yy-axis at point \left( {0, - \,4} \right)(0,−4).

Step-by-step explanation:

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Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
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Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

\large\underline{\sf{Solution-}}

Given expression is

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

On substituting directly x = 1, we get,

\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}

\rm \: = \sf \: \: - \infty \: - \: \infty

which is indeterminant form.

Consider again,

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]

can be rewritten as

\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]

\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]

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\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}

\rule{190pt}{2pt}

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